CODEWITHSUNDEEP
vimfile-type
user5951046
user5951046

Reputation: 3

vi, condition in vimrc

I am trying to personalize my ~/.vimrc file.

Here is what I want: when the file name opened with vi is titi45.tex, and when I press <space> in normal mode, I want that the command make toto45 is executed. And if the file opened with vi is called titi65.tex, I want that make toto65 is executed, and so on.

I tried to use a command

au FileType tex nmap <space> :w<CR>:!make<CR><CR>

in my .vimrc but I don't know how to match the file name and use the number.

Can you help me?

Mathieu

Upvotes: 0

Views: 511

Answers (2)

user5951046
user5951046

Reputation: 3

Hum... finally i use an additionnal script

#!/bin/bash

maRegex='source_(enonce|corrige)([0-9]+)$'

if [[ "${1}" =~ $maRegex ]]
then
        commande="make enonce${BASH_REMATCH[2]}"
else
        commande="make plouf"
fi

echo commande de compilation lancée: $commande
$commande

This script in launched by vimrc.

Upvotes: 0

Luc Hermitte
Luc Hermitte

Reputation: 32926

You are looking for :make %<. BTW why don't you compile within vim? Avoid :!make. Prefer :make, and check the help related to the quickfix mode (:h quickfix).

Your mapping would then be:

nnoremap <buffer> <silent> <space> :update<cr>:make %<<cr>

(the <buffer> part is very important, it makes sure your mapping won't leak to other filetypes; the other are not critical here, but good practices)

EDIT: Sorry I missed the exact requirement.

Then, you'll have to transform the target name. You'll to play with substitute() and :exe. But your substitution won't be a simple substitution. It looks like a rotating substitution. Solutions for this kind of substitution have been described over there: How do I substitute from a list of strings in VIM? And IIIRC, there exist a plugin that does similar things.

In your case, I guess I would use a dictionary to define how names are substituted: 

let k_subs = { 'toto': 'titi', 'titi': 'toto' }
nnoremap <buffer> <silent> <space> :update<cr>:exe 'make '.substitute(expand('%'), join(keys(k_subs), '\|'), '\=k_subs[submatch(0)]', '')cr>

NB: I haven't tested it.

If you want to get rid of the extension, it'd better be done in expand() argument.

Upvotes: 3

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