CODEWITHSUNDEEP
swiftfunctionswift2repeat
user5104686
user5104686

Reputation:

Repeating String in Swift

I'm tasked with creating a function that takes two parameters of a string and int that will return a string that repeats the string parameter the int's number of times. This is what I came up with but getting an error. BTW, this is on CodeCardio that I do at work so I haven't been able to test it out in Xcode (my work sucks and uses Windows)

func repeater(aString: String, withNumber: Int) -> String {
    let repeatedString = String(count: withNumber, repeatedValue: aString)
    return repeatedString
}

Upvotes: 5

Views: 6761

Answers (8)

mrbesford
mrbesford

Reputation: 11

Swift 5:

extension String {
    func repeater(by count: Int) -> String {
        return String(repeating: self, count: count)
    }
}

Calling: "testString".repeater(by: counter)

Upvotes: 1

Nilanshu Jaiswal
Nilanshu Jaiswal

Reputation: 1693

As of Swift 3, init(repeating:count:) can take String arguments as well.

var repeatingString = String(repeating: "ab", count: 7)
print(repeatingString) // ababababababab

Try this:

func repeater(aString: String, withNumber: Int) -> String {
    let repeatedString = String(repeating: aString, count: withNumber)
    return repeatedString
}

Upvotes: 9

fdiaz
fdiaz

Reputation: 2600

You can just do this:

func repeater(aString string: String, withNumber number: Int) -> String {
    return [String](count: number, repeatedValue: string).reduce("", combine: +)
}

Upvotes: 4

user4313581
user4313581

Reputation: 

func repeatAString(anyString: String, numberOfTimes: Int) ->String
{
    var returnString: String = String()
    for _ in 1...numberOfTimes 
    {
        returnString = returnString.stringByAppendingString(anyString)
    }
    return returnString
}

Hi I have used stringByappendingString to solve this one. I see you have plenty of answers but no-one has suggested that so thought Id put it out there. Cheers!

Upvotes: 1

vadian
vadian

Reputation: 285082

The type of argument repeatedValue of String(count: repeatedValue: aCharacter) is a single Character rather than String.

You could use Array(count: withNumber, repeatedValue: aString) and join the items

func repeater(aString: String, withNumber: UInt) -> String {
  let repeatedArray = Array(count: Int(withNumber), repeatedValue: aString)
  return repeatedArray.joinWithSeparator("")
}

Upvotes: 4

user3441734
user3441734

Reputation: 17544

I slightly modify Tanguy's answer. Now, the function will not crash if the second parameter is less than 0, but returns an empty string

func repeate(string: String,  times: Int) -> String {
    var repeatedString = ""
    var n = times
    while n > 0 {
        repeatedString += string
        n -= 1
    }
    return repeatedString
}

the same issue has Vadian's answer, checking the parameter and returning early with "" is probably the best solution. I personally prefer Vadian's approach.

Upvotes: 2

sachin
sachin

Reputation: 11

func repeater(aString: String, withNumber: Int) -> String 
{
var repeatedString=""
for var index = 0; index < withNumber; ++index 
   {
     repeatedString=repeatedString+aString
   }
return repeatedString
}

for Function Call i use: print(repeater("String",withNumber: 5))

Upvotes: 0

tgyhlsb
tgyhlsb

Reputation: 1915

String(count: withNumber, repeatedValue: aString)

Is used to instantiate an string with a repeated character: Does Swift init(count:, repeatedValue:) work?

Instead do

func repeater(string: String, withNumber number: Int) -> String {
    var repeatedString = String()
    for i in 0..<number {
        repeatedString += string
    }
    return repeatedString
}

Upvotes: 13

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