CODEWITHSUNDEEP
python
K.Allman
K.Allman

Reputation: 1

How to find the index of all letters in a user inputted string

This is the assignment: Write a program that gets a single word from the user. For each letter in the word, print the index of that letter in the string 'ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz' (e.g., 'A' would print 0, 'z' would print 51). Print all the indices on one line, separated by spaces.

alphabet = 'ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz'

word = input('Type a word: ')

for ind in word:
    answer = ind.index(alphabet[0,-1])
    print(answer)

My code does not run. It says "TypeError: string indices must be integers". 0 and -1 are both integers, and they indicate the first and last positions of a given string. I don't understand why this is not running properly. The code should take alphabet at position 0, see that there is no matching value in word, and then move on to the next one until it reaches the first character's position in the typed string. It should then print out that number, and keep going. What am I doing wrong?

Upvotes: 0

Views: 6530

Answers (3)

Tom Cupis
Tom Cupis

Reputation: 316

Or you could just use ASCII codes using the ord() function,

word = input("word:")
for i in range(len(word)):
    print(ord(word[i:i+1]), end="")

This will give you a number output from a string and its not just limited to the alphabet

Upvotes: 0

Garrett R
Garrett R

Reputation: 2662

I think you meaning to be following a pattern like this. Get a each character from the input word and find the index in alphabet where the character occurs. 

answer = []
for char in word:
    answer += [alphabet.index(char)]

You can further simplify with a list comprehension

answer = [alphabet.index(char) for char in word]

Upvotes: 1

John Gordon
John Gordon

Reputation: 33351

You're calling index the wrong way. You need to swap the arguments:

answer = alphabet.index(ind)

Upvotes: 1

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