CODEWITHSUNDEEP
linuxbashvariablesubuntuvariable-assignment
harsh atal
harsh atal

Reputation: 409

Bash variable assignment strange behaviour

I am trying to write a bash script, while doing that am stuck here:

I do not understand why this works:

MSG=$(pwd)
echo $MSG

Output:

/home/harsh/source/git/trunk

BUT this does not:

MSG=$(java -version)
echo $MSG

Output:

BLANK

Please help!

Upvotes: 3

Views: 115

Answers (2)

l'L'l
l'L'l

Reputation: 47169

Some commands might need 2>&1 at the end to get any output:

MSG=$(java -version 2>&1)

It sends any standard error(2) to wherever standard output(1) is redirected.

Upvotes: 2

e0k
e0k

Reputation: 7161

Error messages are typically written to the standard error stream stderr instead of the standard output stream stdout. If java -version generates an error instead of what you expected (printing the version), it will likely do so to stderr. It is also possible that the version information could also printed to stderr.

The command substitution $() takes the output from stdout of what's inside the $() and substitutes it in its place. In case of an error, this could be nothing. If you are typing this from a terminal, you should still see any output (e.g. error messages) from java's stderr in the terminal.

Upvotes: 1

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