CODEWITHSUNDEEP
rubyyaml
user3851283
user3851283

Reputation: 347

Store Ruby YAML results into an array

So I have an empty array and a .yml file. I have managed to output the results of that file with this code

puts YAML.load_file('some_yml_file.yml').inspect

I was wondering, how can I pull out each of the data and store them into an empty array?

Is it

emptyarray = []
YAML.load_file('some_yml_file.yml').inspect do |entry|
    emptyarray << entry
end

Any help would be appreciated! Thanks!

Upvotes: 0

Views: 788

Answers (2)

Jordan Running
Jordan Running

Reputation: 106087

YAML.load_file returns a Ruby object corresponding to the type of data structure the YAML represents. If the YAML contains a sequence, YAML.load_file will return a Ruby array. You don't need to do anything further to put the data into an array, because it's already an array:

yaml = <<END
---
- I am
- a YAML
- sequence
END

data = YAML.load(yaml)
puts data.class
# => Array
puts data == ["I am", "a YAML", "sequence"]
# => true

(You'll notice that I used YAML.load to load the data from a string rather than a file, but the result is the same as using YAML.load_file on a file with the same contents.)

If the top-level structure in the YAML is not a sequence (e.g. if it's a mapping, analogous to a Ruby hash), then you will have to do additional work to turn it into an array, but we can't tell you what that code would look like without seeing your YAML.

Upvotes: 1

Nabeel
Nabeel

Reputation: 2302

Change YAML.load_file('some_yml_file.yml').inspect do |entry| with YAML.load_file('some_yml_file.yml').each do |entry| and it should work as you expect it (assuming it's not a string).

If you post a sample of your data structure inside the YAML file and what you wish to extract and put in an array then that would help.

Upvotes: 0

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