CODEWITHSUNDEEP
pythontuplesconcatenation
drowningincode
drowningincode

Reputation: 33

How to concatenate tuples

I have this code:

def make_service(service_data, service_code):
    routes = ()
    curr_route = ()
    direct = ()

    first = service_data[0]
    curr_dir = str(first[1])

    for entry in service_data:
        direction = str(entry[1])
        stop = entry[3]

        if direction == curr_dir:
            curr_route = curr_route + (stop, )
            print((curr_route))

When I print((curr_route)), it gives me this result:

('43009',)
('43189', '43619')
('42319', '28109')
('42319', '28109', '28189')
('03239', '03211')
('E0599', '03531')

How do I make it one tuple? i.e. ('43009','43189', '43619', '42319', '28109', '42319', '28109', '28189', '03239', '03211', 'E0599', '03531')

Upvotes: 1

Views: 8293

Answers (2)

Willbeing
Willbeing

Reputation: 121

tuples = (('hello',), ('these', 'are'), ('my', 'tuples!'))
sum(tuples, ())

gives ('hello', 'these', 'are', 'my', 'tuples!') in my version of Python (2.7.12). Truth is, I found your question while trying to find how this works, but hopefully it's useful to you!

Upvotes: 2

JulienD
JulienD

Reputation: 7293

Tuples exist to be immutable. If you want to append elements in a loop, create an empty list curr_route = [], append to it, and convert once the list is filled:

def make_service(service_data, service_code):
    curr_route = []
    first = service_data[0]
    curr_dir = str(first[1])

    for entry in service_data:
        direction = str(entry[1])
        stop = entry[3]

        if direction == curr_dir:
            curr_route.append(stop)

    # If you really want a tuple, convert afterwards:
    curr_route = tuple(curr_route)
    print(curr_route)

Notice that the print is outside of the for loop, which may be simply what you were asking for since it prints a single long tuple.

Upvotes: 1

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