Reputation: 267
I have a xml with below structure.
<p>Simple XML will return a reference to an <i>object</i> containing: <quote><p>the node value and you cant use references in session variables</p></quote> as there is <b>no feasible</b> way to restore a reference to another variable.</p>
The output should be follow
<p>Simple XML will return a reference to an <i>object</i> containing:<p>
<blockquote>the node value and you cant use references in session variables</blockquote>
<p>as there is <b>no feasible</b> way to restore a reference to another variable.</p>
How is possible to split the tags with emphasis. Thanks in advance.
Upvotes: 0
Views: 122
Reputation: 1069
If you want to do it with XSLT, here's a possible solution:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
exclude-result-prefixes="xs"
version="2.0">
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="quote">
<xsl:text disable-output-escaping="yes"><![CDATA[</p>]]></xsl:text>
<blockquote><xsl:apply-templates select="@*|node()"/></blockquote>
<xsl:text disable-output-escaping="yes"><![CDATA[<p>]]></xsl:text>
</xsl:template>
<xsl:template match="quote/p">
<xsl:value-of select="."/>
</xsl:template>
</xsl:stylesheet>
Upvotes: 2