CODEWITHSUNDEEP
javascriptregex
Kris
Kris

Reputation: 151

Regex to match motor cycle names and extract all letters and numbers separately

(\w{1,4})(?:\s{0,1})(\d{1,4})(?:\s{0,1})(\w{1,4})\s

Apologies if this is really ugly regex but I am not fluent in it at all.

I need a regex function to extract all possible combinations from motor cycle names for instance:

From a Honda CBR500R I would need to get CBR, 500 and R. I am not sure if I regex could give me CBR500 and 500R as that would be really sweet!

Some type of bike names:

Honda CBR500R
CBR 500 R
CBR 500R
CBR500 R
GS1000 S
XYZT 1000P
500ztx
KLR250 Honda
FZR 600 Suzuki
SV650
Text here XXXX 9999 XXXX 9999 XXXXX more text here

Is there a way to improve my regex? making it simpler and smarter?

Upvotes: 1

Views: 136

Answers (2)

Wiktor Stribiżew
Wiktor Stribiżew

Reputation: 627044

You can use

([A-Z]{2,})?[\s-]*(\d+)([a-z]+)?[\s-]*([A-Z]*\b)

See the regex demo

The regex matches:

  • ([A-Z]{2,})? - Group 1: one or zero sequence of 2 or more capital ASCII letters
  • [\s-]* - zero or more - or whitespace symbols
  • (\d+) - Group 2: one or more digits
  • ([a-z]+)? - Group 3: one or zero sequence of one or more ASCII lowercase letters
  • [\s-]* - zero or more - or whitespace symbols
  • ([A-Z]*\b) - Group 4: zero or more ASCII uppercase letters followed by a word boundary.

Here is a sample extraction code in Python:

import re
p = re.compile(r'([A-Z]{2,})?[\s-]*(\d+)([a-z]+)?[\s-]*([A-Z]*\b)')
test_str = "Honda CBR500R\nCBR 500 R\nCBR 500R\nCBR500 R\nGS1000 S\nXYZT 1000P\n500ztx\nKLR250 Honda\nFZR 600 Suzuki\nText here XXXX 9999 XXXX 9999 XXXXX more text here"
for s in p.findall(test_str):
    print("New Entry:")
    for r in s:
        if r:
            print(r)

Output:

New Entry:
CBR
500
R
New Entry:
CBR
500
R
New Entry:
CBR
500
R
New Entry:
CBR
500
R
New Entry:
GS
1000
S
New Entry:
XYZT
1000
P
New Entry:
500
ztx
New Entry:
KLR
250
New Entry:
FZR
600
New Entry:
XXXX
9999
XXXX
New Entry:
9999
XXXXX

Upvotes: 1

Quinn
Quinn

Reputation: 4504

I come up with the following pattern. No sure if it is what you expected (duplicates are not removed):

import re

txt = """
Honda CBR500R
CBR 500 R
CBR 500R
CBR500 R
GS1000 S
XYZT 1000P
500ztx
KLR250 Honda
FZR 600 Suzuki
SV650
Text here XXXX 9999 XXXX 9999 XXXXX more text here
"""

pattern = r'[A-Z]+\d+|\d+[A-Z]|[A-Z]+(?![a-z])|\d+[a-z]+|\d+'
print re.findall(pattern, txt)

Output is:

['CBR500', 'R', 'CBR', '500', 'R', 'CBR', '500R', 'CBR500', 'R', 'GS1000', 'S', 'XYZT', '1000P', '500ztx', 'KLR250', 'FZR', '600', 'SV650', 'XXXX', '9999', 'XXXX', '9999', 'XXXXX']

If you want to capture '500R' from 'CBR500R' also:

p1 = r'[A-Z]+\d+|(?<!\d)[A-Z]+(?![a-z])|\d+[a-z]+|\d+(?![0-9A-Z])'
p2 = r'\d+[A-Z]'
print re.findall(p1, txt) + re.findall(p2, txt)

Output is:

['CBR500', 'CBR', '500', 'R', 'CBR', 'CBR500', 'R', 'GS1000', 'S', 'XYZT', '500ztx', 'KLR250', 'FZR', '600', 'SV650', 'XXXX', '9999', 'XXXX', '9999', 'XXXXX', '500R', '500R', '1000P']

Upvotes: 1

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