CODEWITHSUNDEEP
cpointers
nan
nan

Reputation: 585

Why does the following fragment of C program give this output?

#include <stdio.h>
int main(void) 
 {
  char c[] = "Gate2011";
  char *p = c;
  printf("%s", p+p[3]-p[1]);
  return 0;
}

Output: 2011

Why does it give this output? I tried different combinations and it always gives junk.

Upvotes: 0

Views: 202

Answers (2)

James
James

Reputation: 1

p+p[3]-p[1]
for p is the address of Ram address of string "Gate2011" ; for P[3] - p[1] will make actually a offset of visit to string ,that is 'e' - 'a' = 4 you can count where is it now.

Upvotes: 0

Ferenc Deak
Ferenc Deak

Reputation: 35408

because p[3] = 'e' = 101 and p[1] = 'a' = 97

101 - 97 = 4

p + 4 = address of "2001" in "Gate2001"

interpreted as string ... there you go.

I also do not understand the downvotes :(

Upvotes: 3

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