CODEWITHSUNDEEP
jquery
dazz
dazz

Reputation: 8742

jquery.each multidimensional array

var array1 = {};

array1['one'] = new Array();
array1['one']['data'] = 'some text';
array1['one']['two'] = new Array();
array1['one']['two']['three'] = new Array();
array1['one']['two']['three']['data'] = 'some other text';

$.each(array1, function(key1, value1){
    $.each(value1['two']['three'], function(key1, value1){
        document.write('test');
    }
});

everything works, except it doesnt get to the document.write. Anyone an idea why?

Upvotes: 12

Views: 41987

Answers (3)

Mark Schultheiss
Mark Schultheiss

Reputation: 34168

Note that the Array() replacement is key here with the missing ')'

var array1 = {};

array1['one'] = new Object();
array1['one']['data'] = 'some text';
array1['one']['two'] = new Object();
array1['one']['two']['three'] = new Object();
array1['one']['two']['three']['data'] = 'some other text';

$.each(array1, function(key1, value1) {
    $.each(value1['two']['three'], function(key1, value1) {
        document.write('test');
    });
});

and Another way to write the same thing:(small tweek on the write to reference your object)

var array1 = {};

array1.one = new Object();
array1.one.data = 'some text';
array1.one.two = new Object();
array1.one.two.three = new Object();
array1.one.two.three.data = 'some other text';


$.each(array1, function(key1, value1) {
    $.each(value1['two']['three'], function(key1, value1) {
        document.write('test' + array1.one.data);
    });
});

And finally, with the deprecated new Object() replacement:

var array1 = {};

array1['one'] = {}
array1['one']['data'] = 'some text';
array1['one']['two'] = {};
array1['one']['two']['three'] = {};
array1['one']['two']['three']['data'] = 'some other text';

$.each(array1, function(key1, value1) {
    $.each(value1['two']['three'], function(key1, value1) {
        document.write('test');
    });
});

EDIT: some fun with your array, and why you MIGHT have the strings in the object declaration as you have it:

var array1 = {}; 
var fun="four"; 
array1.one = {}; 
array1.one.data = 'some text'; 
array1.one.two = {}; 
array1.one.two.three = {}; 
array1.one.two.three.data = 'some other text'; 
array1.one.two[fun] = {};
array1.one.two[fun].data=' howdy';

$.each(array1, function(key1, value1) { 
    $.each(value1.two.three, function(key1, value1) { 
        document.write('test'+array1.one.two[fun].data+ ":"+key1+":"+value1); 
    }); 
});

the output the the last is: "test howdy:data:some other text"

Upvotes: 12

Topera
Topera

Reputation: 12389

You miss ) in the second each.

Upvotes: 1

ConroyP
ConroyP

Reputation: 41916

The document.write isn't working as you've a syntax error, so the code flow never gets to it - you need another bracket at the end of your each, i.e.

$.each(array1, function(key1, value1){
    $.each(value1['two']['three'], function(key1, value1){
        document.write('test');
    })
});

If you're going to be doing any non-trivial work with javascript, I'd highly recommend that you use Firefox with Firebug installed - it's console highlights these kind of errors which would otherwise fail without you realising, leading you to believe everything was working ok.

Upvotes: 1

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