Reputation: 636
I have a text box where I search database for a specific information.
The PHP code when I just type and click on search is the following:
try
{
$date_emp = $_POST['date_emp'];
$val = $_POST['data1'];
$gender = $_POST['gen'];
if($date_emp == "choose" && $gender == "specify")
{
$search = "SELECT * FROM employee
WHERE emp_name = :val OR position = :val
OR salary = :val OR date_employed = :val
OR gender = :val";
$searchStmt = $conn->prepare($search);
$searchStmt->bindValue(":val", $val);
$searchStmt->execute();
$res = $searchStmt->fetchAll();
echo json_encode($res);
}
catch(PDOException $ex)
{
echo $ex->getMessage();
}
And here the AJAX script for it:
$("#search").click(function()
{
var txt = $("#txtSearch").val();
var drop = $("#date_employed").val();
var gender = $("#sex").val();
//console.log(txt);
if(txt == '' && drop == "choose" && gender == "specify")
{
$("#txtSearch").css('border-color', 'red');
}
else
{
if(drop == "choose" && gender == "specify")
{
$.ajax
({
url: 'search.php',
type: 'POST',
data: {data1: txt, date_emp: drop, gen: gender},
dataType: 'JSON',
success:function(res)
{
$("#myTable tr").remove();
$("#myTable").append("<tr><th>Name</th><th>Position</th><th>Salary</th><th>Date</th><th>Gender</th></tr>");
$.each( res, function(key, row){
$("#myTable").append("<tr><td>"+row['emp_name']+"</td><td>"+row['position']+"</td><td>"+row['salary']+"</td><td>"+row['date_employed']+"</td><td>"+row['gender']+"</td></tr>");
});
},
error:function(res)
{
alert("Something Wrong");
}
});
}
$("#date_employed, #sex").change(function()
{
var txt = $("#txtSearch").val();
var drop = $("#date_employed").val();
var gender = $("#sex").val();
$.ajax({
url: 'search.php',
type: 'post',
data: {data1: txt, date_emp: drop, gen: gender},
datatype: 'json',
success:function(res)
{
$("#myTable tr").remove();
$("#myTable").append("<tr><th>Name</th><th>Position</th><th>Salary</th><th>Date</th><th>Gender</th></tr>");
$.each( res, function(key, row){
$("#myTable").append("<tr><td>"+row['emp_name']+"</td><td>"+row['position']+"</td><td>"+row['salary']+"</td><td>"+row['date_employed']+"</td><td>"+row['gender']+"</td></tr>");
});
},
error:function(res)
{
alert("Couldn't find any data!");
}
});
});
}
});
WHERE gender and drop are 2 drop lists that forming a search filters
When I change one of the drop lists, per example, when I choose the date equal to: this week
I should see in table 2 rows.
But I can only see them in the network (in devTool), and at console tab I see the following error:
Uncaught TypeError: Cannot use 'in' operator to search for 'length' in [{"id":"48","0":"48","emp_name":"Alexa","1":"Alexa","position":"Secretary","2":"Secretary","salary":"8000","3":"8000","date_employed":"2016-02-23","4":"2016-02-23","gender":"female","5":"female"}]
The PHP code when I change drop lists is:
if($date_emp == "week" && $gender == "specify")
{
$search = "SELECT * FROM employee WHERE (emp_name = :val OR position = :val
OR salary = :val OR date_employed = :val
OR gender = :val) AND date_employed > DATE_SUB(NOW(), INTERVAL 1 WEEK)";
$searchStmt = $conn->prepare($search);
$searchStmt->bindValue(":val", $val);
$searchStmt->execute();
$res = $searchStmt->fetchAll();
echo json_encode($res);
}
Upvotes: 1
Views: 44
Reputation: 725
When you make an ajax call and expect the response to be a json you need to send a json header from the PHP
header('Content-Type: application/json');
echo json_encode($data);
Sending the json header from the PHP will turn the "res" param in your ajax to a json object and not a json string. If you don't send the the header you need to parse the json string into a json object
var json = JSON.parse(res);
Upvotes: 2