CODEWITHSUNDEEP
javaregexstring
cybertextron
cybertextron

Reputation: 10961

Splitting a string based on a number/char pattern - Java

I want to split a string with the following patterns:

abc3xab     -> ('abc', '3xa', 'b')
abc3x3xab   -> ('abc', '3x3x', 'ab')
abc3xxab    -> ('abc', '3xx', 'ab')
abc34xxab   -> ('abc', '34xx', 'ab')
abc100ab    -> ('abc100ab')
abc10axb    -> ('abc10axb')

That's it, the pattern is '[0-9]+x[a-z]' (if there's a number followed by an 'x' and any char between a-z. I tried

String[] words = string.split("[0-9]+x")

but then I only got abc and ab. What would be the correct way to do it?

Upvotes: 2

Views: 70

Answers (1)

M A
M A

Reputation: 72854

Try using a combination of positive lookahead and lookbehind to keep the delimiter:

String[] words = string.split("((?<=[0-9]+x)|(?=[0-9]+x))");

Sample IDEONE demo:

String[] words = "abc3xab".split("((?<=[0-9]+x)|(?=[0-9]+x))");
System.out.println(Arrays.toString(words));
String[] words1 = "abc3xxab".split("((?<=[0-9]+x)|(?=[0-9]+x))");
System.out.println(Arrays.toString(words1));
String[] words2 = "abc34xxab".split("((?<=[0-9]+x)|(?=[0-9]+x))");
System.out.println(Arrays.toString(words2));
String[] words3 = "abc100ab".split("((?<=[0-9]+x)|(?=[0-9]+x))");
System.out.println(Arrays.toString(words3));
String[] words4 = "abc10axb".split("((?<=[0-9]+x)|(?=[0-9]+x))");
System.out.println(Arrays.toString(words4));

Results:

[abc, 3x, ab]
[abc, 3x, xab]
[abc, 3, 4x, xab]
[abc100ab]
[abc10axb]

Upvotes: 2

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