CODEWITHSUNDEEP
asp.netasp.net-mvcasp.net-mvc-4razor
F Msw
F Msw

Reputation: 131

How to return ViewModel PagedList [ASP MVC]

I'm trying to return a category page with paging .... I got a problem with that in my view , I can't handle the View Model Members , and can't to control them ...

Here is my ViewModel:

public class CategoryVm
{
    public List<Book> Book { set; get; }

    public Category Category_Content { get; set; }

    
}

Also here is the controller :

public ActionResult Category(int? id, int? page)
    {
        int pageSize = 6;
        int pageNumber = page ?? 1;
        if (id != null)
        {
            var vm = new CategoryVm();
            vm.Category_Content = db.Categories.Where(t => t.Category_id == id).Single();
            vm.Book = db.Books.Where(b => b.Category_id == id).ToList();
            if (vm != null)
            {
                //Here I have the problem , it telling me that 'CategoryVm' does not contain a definition for 'ToPagedList'
                return View(vm.ToPagedList(pageNumber, pageSize));

            }
            return HttpNotFound();
        }

        return RedirectToAction("index",new { Controller = "Home" });
    }

and here is my view :

@using PagedList.Mvc
@model PagedList.IPagedList<SmartBookLibrary.ViewModel.CategoryVm>

@{
    ViewBag.Title = Model.Category_Content.Category_name+ " - Smart Books Library";
}

    <div class="container">

    <div class="row">

        <div class="col-md-3">
            <p class="lead">Categories</p>
            <div class="list-group">
                <a href="#" class="list-group-item">Developers</a>
            </div>
        </div>

        <div class="col-md-9">

            

            <div class="row">
@foreach (var item in Model.Book)
{
                
                <div class="col-sm-4 col-lg-4 col-md-4">

                    <figure class="snip1091 navy">
                        <img src="~/Images/@item.Book_Image" alt="sq-sample6" />
                        <figcaption>
                            <label>@item.Book_name</label>
                        </figcaption><a href="/Category/@item.Category.Category_id"></a>
                    </figure>


                    
                </div>
}


            </div>
            Page @(Model.PageCount < Model.PageNumber ? 0 : Model.PageNumber) of @Model.PageCount
            @Html.PagedListPager(Model, page => Url.Action("Category", new {page}))


        </div>

    </div>

</div>

I the view I can't access the model :

ViewBag.Title = Model.Category_Content

@foreach (var item in Model.Book)

so how to fix that , and make the paging work ??

Upvotes: 1

Views: 3646

Answers (2)

Nkosi
Nkosi

Reputation: 247641

Update your view model to use the Paged list 

public class CategoryVm {
    public IPagedList<Book> Book { set; get; }

    public Category Category_Content { get; set; }
}

Then assign the paged list to your view model 

public ActionResult Category(int? id, int? page) {
    int pageSize = 6;
    int pageNumber = page ?? 1;
    if (id != null) {
        var vm = new CategoryVm();
        vm.Category_Content = db.Categories.Where(t => t.Category_id == id).Single();
        var books = db.Books.Where(b => b.Category_id == id).ToList();
        if (vm != null) {
            //Apply paged list to view model.
            vm.Books = books.ToPagedList(pageNumber, pageSize);
            return View(vm);
        }
        return HttpNotFound();
    }

    return RedirectToAction("index",new { Controller = "Home" });
}

Now in your view change the model.

@model SmartBookLibrary.ViewModel.CategoryVm

And 

Page @(Model.Book.PageCount < Model.Book.PageNumber ? 0 : Model.Book.PageNumber) of @Model.Book.PageCount
        @Html.PagedListPager(Model.Book, page => Url.Action("Category", new {page}))

Upvotes: 3

ManojAnavatti
ManojAnavatti

Reputation: 644

According to here ToPageList will be applied to IEnumerable or IQueryable: https://github.com/troygoode/PagedList

        var vm = new CategoryVm();
        vm.Category_Content = db.Categories.Where(t => t.Category_id == id).Single();
        vm.Book = db.Books.Where(b => b.Category_id == id).ToList();
        if (vm != null)
        {
            var newListCategoryVm = new List<CategoryVm>() {vm}

            return View(newListCategoryVm.ToPagedList(pageNumber, pageSize));

        }

In the view you know now that you need to for each or whatever you like.

Upvotes: 1

Related Questions