CODEWITHSUNDEEP
iphoneobjective-cstringint
Christian Stewart
Christian Stewart

Reputation: 15519

ObjectiveC Parse Integer from String

I'm trying to extract a string (which contains an integer) from an array and then use it as an int in a function. I'm trying to convert it to a int using intValue.

Here's the code I've been trying.

  NSArray *_returnedArguments = [serverOutput componentsSeparatedByString:@":"];
  [_appDelegate loggedIn:usernameField.text:passwordField.text:(int)[[_returnedArguments objectAtIndex:2] intValue]];

I get this error:

passing argument 3 of 'loggedIn:::' makes pointer from integer without a cast

What's wrong?

Upvotes: 123

Views: 134172

Answers (6)

Albert Renshaw
Albert Renshaw

Reputation: 17892

Keep in mind that international users may be using a decimal separator other than . in which case values can get mixed up or just become nil when using intValue on a string.

For example, in the UK 1.23 is written 1,23, so the number 1.777 would be input by user as 1,777, which, as .intValue, will be 1777 not 1 (truncated).

I've made a macro that will convert input text to an NSNumber based on a locale argument which can be nil (if nil it uses device current locale).

#define stringToNumber(__string, __nullable_locale) (\
(^NSNumber *(void){\
NSLocale *__locale = __nullable_locale;\
if (!__locale) {\
__locale = [NSLocale currentLocale];\
}\
NSString *__string_copy = [__string stringByReplacingOccurrencesOfString:__locale.groupingSeparator withString:@""];\
__string_copy = [__string_copy stringByReplacingOccurrencesOfString:__locale.decimalSeparator withString:@"."];\
return @([__string_copy doubleValue]);\
})()\
)

Upvotes: 0

Danyun Liu
Danyun Liu

Reputation: 3092

You can just convert the string like that [str intValue] or [str integerValue]

integerValue Returns the NSInteger value of the receiver’s text.

  • (NSInteger)integerValue Return Value The NSInteger value of the receiver’s text, assuming a decimal representation and skipping whitespace at the beginning of the string. Returns 0 if the receiver doesn’t begin with a valid decimal text representation of a number.

for more information refer here

Upvotes: 8

Christian Stewart
Christian Stewart

Reputation: 15519

I really don't know what was so hard about this question, but I managed to do it this way:

[myStringContainingInt intValue];

It should be noted that you can also do:

myStringContainingInt.intValue;

Upvotes: 271

beefon
beefon

Reputation: 3192

If I understood you correctly, you need to convert your NSString to int? Try this peace of code:

NSString *stringWithNumberInside = [_returnedArguments objectAtIndex:2];
int number;
sscanf([stringWithNumberInside UTF8String], "%x", &flags);

Upvotes: -1

falconcreek
falconcreek

Reputation: 4170

NSArray *_returnedArguments = [serverOutput componentsSeparatedByString:@":"];

_returnedArguments is an array of NSStrings which the UITextField text property is expecting. No need to convert.

Syntax error:

[_appDelegate loggedIn:usernameField.text:passwordField.text:(int)[[_returnedArguments objectAtIndex:2] intValue]];

If your _appDelegate has a passwordField property, then you can set the text using the following

[[_appDelegate passwordField] setText:[_returnedArguments objectAtIndex:2]];

Upvotes: 1

Jorge Israel Peña
Jorge Israel Peña

Reputation: 38586

Basically, the third parameter in loggedIn should not be an integer, it should be an object of some kind, but we can't know for sure because you did not name the parameters in the method call. Provide the method signature so we can see for sure. Perhaps it takes an NSNumber or something.

Upvotes: 0

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