CODEWITHSUNDEEP
phparraysjsonstring
Dhruvee Patel
Dhruvee Patel

Reputation: 3

Remove double quotes from the Json_encode result

I'm trying to fatch some data frm database, and trying to create a new json file. However, in my output I'm getting double quotes in the array.

I tried many solutions available on Stack Overflow but no success so far. Help me remove it.

   $to=array("name" => "Today","data" => $count1);
   $yes=array("name" => "Yesterday","data" => $count2);
   $ab=array($to,$yes);
   $y=array("format" => "percent");
   $z=array("labels" => $ti);

  $json=json_encode(array("series" => $ab,"y_axis" => $y,"x_axis" => $z));

     $fp = fopen('data.json', 'w');
      fwrite($fp, $json);
     fclose($fp);

Current output:

{
    "series": [
        {
             "name":"Today","data":["123","123","123"]
        }
    ],
    "y_axis": {
        "format":"percent"
    },
    "x_axis": {
        "labels": ["00:00","00:00","00:00"]
    }
}

I don't need double quotes around 123 & 00:00.

Upvotes: 0

Views: 1131

Answers (3)

Gardax
Gardax

Reputation: 370

Try casting all the integer values to integer (you can cast to float with the floatval() function):

$to=array("name" => "Today","data" => (int)$count1);

EDIT: I have missed that the $count1 is an array. You can cast all the elements of the array to integer.

function castArrayOfStingsToArrayOfIntegers(&$array){
    foreach ($array as $key => $var) {
        $array[$key] = (int)$var;
    }
}

castArrayOfStingsToArrayOfIntegers($count1)

You can use any other way to traverse the elements. Consider that it will have minimalistic performance impact if you have a lot of values in the array. You should think if you really need this values as integers and if this is the correct place to cast them. It can be better to cast them while you are constructing the $count1 and other similar arrays.

SECOND EDIT: If you have a lot of items keep in mind that the cast using (int) is a lot faster(around 2 times) than the intval() function.

Upvotes: 0

Kheshav Sewnundun
Kheshav Sewnundun

Reputation: 1244

You can use array_map to convert your $count1 variable to integer as follows:

$to = array("name" => "Today","data" => array_map('intval',$count1));

[Proof of concept]

<?php

$count1 = array("1","2","00:00","10");


$to = array("name" => "Today","data" => array_map('intval',$count1));
var_dump($to);
?>

Result:

array(2) {
  ["name"]=>
  string(5) "Today"
  ["data"]=>
  array(4) {
    [0]=>
    int(1)
    [1]=>
    int(2)
    [2]=>
    int(0)
    [3]=>
    int(10)
  }
}

Upvotes: 0

Fakhruddin Ujjainwala
Fakhruddin Ujjainwala

Reputation: 2553

Try this:

For no values use floatval($var); Ref: http://php.net/manual/en/function.floatval.php

Current output: 

{"series":[{"name":"Today","data":["123","123","123"]}], "y_axis":{"format":"percent"},"x_axis":{"labels":["00:00","00:00","00:00"]}}

Handle "123","123","123" using floatval($var); and ["00:00","00:00","00:00"] will come in double quotes as its strings.

Upvotes: 1

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