CODEWITHSUNDEEP
bashdocker
jwi
jwi

Reputation: 1178

Docker exec in bash script

I'm creating dynamically docker containers via bash script: 

while getopts ":s:d:h" opt; do
    case $opt in
        s)
            for i in $(seq $2 $END); 
                do 
                    docker run -dit --name=app_client_$i -d app:client
                    docker exec -d app_client_$i $app_start
            done
            ;;
...

The docker container starts fine, but the docker exec command caused problems. When I try (without the -d):

docker exec app_client_$i $app_start

The application inside the docker container starts fine - but I'm attached to this docker container. I want to start the app inside the docker container in the background, so I use the -d parameter:

docker exec -d app_client_$i $app_start

With that the app doesn't start inside the docker container. What I am missing?

Upvotes: 2

Views: 1661

Answers (1)

jwi
jwi

Reputation: 1178

Okay, got it (facepalm):

With the docker -d you're going to start the process INSIDE the container in the background. So my app was already running inside the container, but in the background.

Cheers!

Upvotes: 2

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