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javaregex
Paul Brady
Paul Brady

Reputation: 73

Java Regex Find/replace

I have the following string

aaaa#include(soap1.xml)bbbb #include(soap2.xml)cccc #include(soap2.xml)

I want to find all occurrences of #include([anyfilename]) where [anyfilename] varies.

I have the regex (?<=#include\()(.*?)(?=\)*\)) which matches [anyfilename] but then performing a replace using this leaves behind there #include()

Can someone suggest show me how to find/replace the entire #include([anyfilename])?

Upvotes: 2

Views: 118

Answers (1)

Wiktor Stribiżew
Wiktor Stribiżew

Reputation: 627468

You may use the following regex:

#include\(([^)]*)\)

See the regex demo

I replaced lookarounds (that are zero-width assertions and do not consume text, do not return it in the match value) with consuming equivalents.

The regex breakdown:

  • #include\( - match a sequence of literal symbols #include(
  • ([^)]*) - Group 1 (we'll refer to the value inside the group with matcher.group(1)) matching zero or more characters other than )
  • \) - match a literal )

The same pattern can be used to retrieve the filenames, and remove whole #include()s from the input.

IDEONE demo:

String str = "aaaa#include(soap1.xml)bbbb#include(soap2.xml)cccc";
String p = "#include\\(([^)]*)\\)";
Pattern ptrn = Pattern.compile(p);
Matcher matcher = ptrn.matcher(str);
List<String> arr = new ArrayList<String>();
while (matcher.find()) {
    arr.add(matcher.group(1));       // Get the Group 1 value, file name
}
System.out.println(arr); // => [soap1.xml, soap2.xml]
System.out.println(str.replaceAll(p, "")); // => aaaabbbbcccc

Upvotes: 1

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