CODEWITHSUNDEEP
iosswift
AamirR
AamirR

Reputation: 12198

variable value causing error: IR generation failure program too clever

Here is the simple code that causing problem:

class CoreViewController: UIViewController {
    private let isPad = UI_USER_INTERFACE_IDIOM() == .Pad
}

Following is the erorr message

<unknown>:0: error: IR generation failure: program too clever: variable collides with existing symbol OBJC_CLASS_$_UIDevice

No error, if I remove UI_USER_INTERFACE_IDIOM() == .Pad

Any thoughts?

Upvotes: 1

Views: 46

Answers (2)

Rafał Sroka
Rafał Sroka

Reputation: 40030

UI_USER_INTERFACE_IDIOM will NOT work in Swift, it's an Objective-C macro.

Solution

Option 1. Use UIDevice.currentDevice().userInterfaceIdiom instead.

switch UIDevice.currentDevice().userInterfaceIdiom {
    case .Phone:
        // It's an iPhone
    case .Pad:
        // It's an iPad
    case .Unspecified:
        // Undefined
    }

Option 2. Request an UITraitCollection instance and check the idiom (recommended)

let deviceIdiom = UIScreen.mainScreen().traitCollection.userInterfaceIdiom

switch (deviceIdiom) {

case .Pad:
        // It's an iPad
case .Phone:
        // It's an iPhone
case .TV: 
        // Apple TV
default:
        // Undefined    
}

Upvotes: 2

Duncan C
Duncan C

Reputation: 131418

I believe UI_USER_INTERFACE_IDIOM is a macro. It might not work from Swift.

Upvotes: 2

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