CODEWITHSUNDEEP
javascripturl
Spadaboyz
Spadaboyz

Reputation: 369

JavaScript get url segment and parameter

I've read some question but I still can't figure out how to do it
I have a url example.com/event/14aD9Uxp?p=10

Here I want to get the 14aD9Uxp and the value of p
I've tried using split('/'+'?p=') but it doesn't work
I want to use regex but I dont really understand how to use it

Upvotes: 11

Views: 31090

Answers (5)

David Yue
David Yue

Reputation: 725

I've created a generalized function (restricted in some ways) that will return the GET value given the parameter. However this function will only work correctly provided that you do not Rewrite the URL or modify the URL GET SYNTAX.

//Suppose this is your URL "example.com/event/14aD9Uxp?p=10";
            function GET(variable) {
                var str = window.location.href;


                str = str.split("/");
                // str = [example.com, event, 14aD9Uxp?p=10]


                //Get last item from array because this is usually where the GET parameter is located, then split with "?"
                str = str[str.length - 1].split("?");
                // str[str.length - 1] = "14aD9Uxp?p=10"
                // str[str.length - 1].split("?") = [14aD9Uxp, p=10]

                // If there is more than 1 GET parameter, they usually connected with Ampersand symbol (&). Assuming there is more, we need to split this into another array

                str = str[1].split("&");
                // Suppose this is your URL: example.com/event/14aD9Uxp?p=10&q=112&r=119
                // str = [p=10, q=112, r=119]
                // If there is only 1 GET parameter, this split() function will not "split" anything

                //Remember, there might only be 1 GET Parameter, so lets check length of the array to be sure.
                if (str.length > 1) {
                    
                    // This is the case where there is more than 1 parameter, so we loop over the array and filter out the variable requested
                    for (var i = 0; i < str.length; i++) {

                        // For each "p=10" etc. split the equal sign 
                        var param_full_str = str[i].split("=");
                        // param_full_str = [p, 10]

                        //Check if the first item in the array (your GET parameter) is equal to the parameter requested
                        if (param_full_str[0] == variable) {
                            // If it is equal, return the second item in the array, your GET parameter VALUE
                            return param_full_str[1];
                        }
                    }
                } else {
                    // This is the case where there is ONLY 1 GET parameter. First convert it to a String Type because Javascript decided that str was no longer a String
                    // Now split it with the equal sign.
                    str = str.toString().split("=");
                    return str[1];
                }
            }
            document.write(GET("p"));

Upvotes: 3

c01nd01r
c01nd01r

Reputation: 617

const url = new URL('http://example.com/event/14aD9Uxp?p=10');

const [,, eventId ] = url.pathname.split('/');
const p = url.searchParams.get('p');

Browser support:
https://caniuse.com/#feat=url
https://caniuse.com/#feat=urlsearchparams

Upvotes: 2

David G
David G

Reputation: 6871

function $_GET(param) {
    var vars = {};
    window.location.href.replace( 
        /[?&]+([^=&]+)=?([^&]*)?/gi, // regexp
        function( m, key, value ) { // callback
            vars[key] = value !== undefined ? value : '';
        }
    );

    if ( param ) {
        return vars[param] ? vars[param] : null;    
    }
    return vars;
}

I have collected this from here: http://www.creativejuiz.fr/blog/javascript/recuperer-parametres-get-url-javascript It works great.

To use it just grab your parameter like:

var id = $_GET('id');

Upvotes: 1

wandering-geek
wandering-geek

Reputation: 1380

Simple no-regex way

var s = "example.com/event/14aD9Uxp?p=10";
var splitByForwardSlash = s.split('/');

// To get 14aD9Uxp
splitByForwardSlash[splitByForwardSlash.length-1]

// To get p=10
splitByForwardSlash[splitByForwardSlash.length-1].split('?')[1]

I think you know how to go from here :-)

Upvotes: 0

Flake
Flake

Reputation: 1406

var URL='example.com/event/14aD9Uxp?p=10';

var arr=URL.split('/');//arr[0]='example.com'
                       //arr[1]='event'
                       //arr[2]='14aD9Uxp?p=10'

var parameter=arr[arr.length-1].split('?');//parameter[0]='14aD9Uxp'
                                           //parameter[1]='p=10'

var p_value=parameter[1].split('=')[1];//p_value='10';

Upvotes: 15

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