Numbers to words along with decimal value count

Question

I am trying to convert numbers to text but when I'm trying to convert number along with decimal value that is not showing up but when only number is entered with out decimal value that works perfect and the decimal value is MAX 2 digits am not sure how too do that.

JS Fiddle

HTML:

<input type="text" name="number" placeholder="Number OR Amount" onkeyup="word.innerHTML=convertNumberToWords(this.value)" />
<div id="word"></div>

JavaScript:

function convertNumberToWords(amount) {
    var words = new Array();
    words[0] = '';
    words[1] = 'One';
    words[2] = 'Two';
    words[3] = 'Three';
    words[4] = 'Four';
    words[5] = 'Five';
    words[6] = 'Six';
    words[7] = 'Seven';
    words[8] = 'Eight';
    words[9] = 'Nine';
    words[10] = 'Ten';
    words[11] = 'Eleven';
    words[12] = 'Twelve';
    words[13] = 'Thirteen';
    words[14] = 'Fourteen';
    words[15] = 'Fifteen';
    words[16] = 'Sixteen';
    words[17] = 'Seventeen';
    words[18] = 'Eighteen';
    words[19] = 'Nineteen';
    words[20] = 'Twenty';
    words[30] = 'Thirty';
    words[40] = 'Forty';
    words[50] = 'Fifty';
    words[60] = 'Sixty';
    words[70] = 'Seventy';
    words[80] = 'Eighty';
    words[90] = 'Ninety';
    amount = amount.toString();
    var atemp = amount.split(".");
    var number = atemp[0].split(",").join("");
    var n_length = number.length;
    var words_string = "";
    if (n_length <= 9) {
        var n_array = new Array(0, 0, 0, 0, 0, 0, 0, 0, 0);
        var received_n_array = new Array();
        for (var i = 0; i < n_length; i++) {
            received_n_array[i] = number.substr(i, 1);
        }
        for (var i = 9 - n_length, j = 0; i < 9; i++, j++) {
            n_array[i] = received_n_array[j];
        }
        for (var i = 0, j = 1; i < 9; i++, j++) {
            if (i == 0 || i == 2 || i == 4 || i == 7) {
                if (n_array[i] == 1) {
                    n_array[j] = 10 + parseInt(n_array[j]);
                    n_array[i] = 0;
                }
            }
        }
        value = "";
        for (var i = 0; i < 9; i++) {
            if (i == 0 || i == 2 || i == 4 || i == 7) {
                value = n_array[i] * 10;
            } else {
                value = n_array[i];
            }
            if (value != 0) {
                words_string += words[value] + " ";
            }
            if ((i == 1 && value != 0) || (i == 0 && value != 0 && n_array[i + 1] == 0)) {
                words_string += "Crores ";
            }
            if ((i == 3 && value != 0) || (i == 2 && value != 0 && n_array[i + 1] == 0)) {
                words_string += "Lakhs ";
            }
            if ((i == 5 && value != 0) || (i == 4 && value != 0 && n_array[i + 1] == 0)) {
                words_string += "Thousand ";
            }
            if (i == 6 && value != 0 && (n_array[i + 1] != 0 && n_array[i + 2] != 0)) {
                words_string += "Hundred and ";
            } else if (i == 6 && value != 0) {
                words_string += "Hundred ";
            }
        }
        words_string = words_string.split("  ").join(" ");
    }
    return words_string;
}

Answer 1

I found the solution for this...

function convertToIndianWords(amount) {
    const units = ['', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight', 'nine'];
    const teens = ['eleven', 'twelve', 'thirteen', 'fourteen', 'fifteen', 'sixteen', 'seventeen', 'eighteen', 'nineteen'];
    const tens = ['', 'ten', 'twenty', 'thirty', 'forty', 'fifty', 'sixty', 'seventy', 'eighty', 'ninety'];
    const scales = ['', 'thousand', 'lakh', 'crore'];

    function convertToWordsLessThanThousand(n) {
        if (n < 10) {
            return units[n];
        } else if (n < 20) {
            return teens[n - 11];
        } else if (n < 100) {
            return tens[Math.floor(n / 10)] + (n % 10 !== 0 ? ' ' + units[n % 10] : '');
        } else {
            return units[Math.floor(n / 100)] + ' hundred' + (n % 100 !== 0 ? ' and ' + convertToWordsLessThanThousand(n % 100) : '');
        }
    }

    function convertAmountToWords(amount) {
        let wholePart = Math.floor(amount);
        const decimalPart = Math.round((amount - wholePart) * 100); // considering up to two decimal places

        const wholeWords = convertToWordsLessThanThousand(wholePart);
        const decimalWords = decimalPart > 0 ? 'and ' + convertToWordsLessThanThousand(decimalPart) + ' paise' : '';

        if (wholeWords === 'zero') {
            return 'zero rupees only';
        }

        const words = [];
        let scaleIndex = 0;

        while (wholePart > 0) {
            const chunk = wholePart % 1000;
            if (chunk !== 0) {
                words.unshift(convertToWordsLessThanThousand(chunk) + ' ' + scales[scaleIndex]);
            }
            wholePart = Math.floor(wholePart / 1000);
            scaleIndex++;
        }

        return words.join(' ') + ' rupees ' + decimalWords +' only';
    }

    return convertAmountToWords(amount);
}

// Example usage:
const amount = 5994.40;
const amountInWords = convertToIndianWords(amount);

console.log(amountInWords);

Answer 2

I used Mr.isvforall's idea added little for my application of eCheck pritning.

function withDecimal(n) {
    var nums = n.toString().split('.')
    var whole = convertNumberToWords(nums[0])
    if (nums.length == 2) {
        var fraction = convertNumberToWords(nums[1])
      //  return whole + 'and ' + fraction;
        return whole + 'and ' +  nums[1] + "/100";
    } else {
        return whole;
    }
}

Answer 3

Use the same function for getting the whole and the decimal part

function withDecimal(n) {
    var nums = n.toString().split('.')
    var whole = convertNumberToWords(nums[0])
    if (nums.length == 2) {
        var fraction = convertNumberToWords(nums[1])
        return whole + 'and ' + fraction;
    } else {
        return whole;
    }
}

console.log(withDecimal(51.32)) //Fifty One and Thirty Two
console.log(withDecimal(29.0))  //Twenty Nine

Answer 4

I found another solution for your problem.

var th = ['', 'thousand', 'million', 'billion', 'trillion'];

var dg = ['zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight', 'nine'];
var tn = ['ten', 'eleven', 'twelve', 'thirteen', 'fourteen', 'fifteen', 'sixteen', 'seventeen', 'eighteen', 'nineteen'];
var tw = ['twenty', 'thirty', 'forty', 'fifty', 'sixty', 'seventy', 'eighty', 'ninety'];
function toWords(s) {
    s = s.toString();
    s = s.replace(/[\, ]/g, '');
    if (s != parseFloat(s)) return 'not a number';
    var x = s.indexOf('.');
    if (x == -1) x = s.length;
    if (x > 15) return 'too big';
    var n = s.split('');
    var str = '';
    var sk = 0;
    for (var i = 0; i < x; i++) {
        if ((x - i) % 3 == 2) {
            if (n[i] == '1') {
                str += tn[Number(n[i + 1])] + ' ';
                i++;
                sk = 1;
            } else if (n[i] != 0) {
                str += tw[n[i] - 2] + ' ';
                sk = 1;
            }
        } else if (n[i] != 0) {
            str += dg[n[i]] + ' ';
            if ((x - i) % 3 == 0) str += 'hundred ';
            sk = 1;
        }
        if ((x - i) % 3 == 1) {
            if (sk) str += th[(x - i - 1) / 3] + ' ';
            sk = 0;
        }
    }
    if (x != s.length) {
        var y = s.length;
        str += 'point ';
        for (var i = x + 1; i < y; i++) str += dg[n[i]] + ' ';
    }
    return str.replace(/\s+/g, ' ');
}