CODEWITHSUNDEEP
bashsymlink
Cito
Cito

Reputation: 53

How to check if file has a symlink

I am writing a bash shell script (for RH and Solaris) that uses openssl to create hash symlinks to certificates all within the same directory. I have approx 130 certificates and when new certs are added I would like the script to create symlinks for the new certs only. I may have to resort to deleting all symlinks and recreating them but if there is a not-so-difficult way to do this; that is preferable than deleting all and recreating.

I know how to find all files with symlinks:

find . -lname '*.cer'

or 

find . -type l -printf '%p -> %l\n'

But I am not sure how to negate or find the inverse of this result in a for or other loop. I want to find all files in the current directory missing a symlink.

Thanks!

Upvotes: 5

Views: 7733

Answers (2)

mklement0
mklement0

Reputation: 437080

Assuming GNU find (whose use I infer from your use of nonstandard action -printf), the following command will output the names of all files in the current directory that aren't the target of symlinks located in the same directory:

comm -23 <(find . -maxdepth 1 -type f -printf '%f\n' | sort) \
         <(find . -maxdepth 1 -lname '*' -printf '%l\n' | sort)

Note: This assumes that the symlinks were defined with a mere filename as the target.
Also, GNU find doesn't sort the output, so explicit sort commands are needed.

You can process the resulting files in a shell loop to create the desired symlinks.

comm -23 <(find . -maxdepth 1 -type f -printf '%f\n' | sort) \
         <(find . -maxdepth 1 -lname '*' -printf '%l\n' | sort) |
  while IFS= read -r name; do ln -s "$name" "${name}l"; done

(In the above command, l is appended to the target filename to form the symlink name, as an example.)

Upvotes: 2

XaviOutside
XaviOutside

Reputation: 141

$ ls -srlt
example1.png
example.png -> ../example.png


$ find . -type f -print
./example1.png


$ find . ! -type f -print
.
./example.png

Upvotes: 3

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