Reputation: 129
<?= $this->Form->create('Asc201516', array(
'url' => array(
'controller' => 'asc201516s',
'action' => 'submit_asc201516'
),
'class' => 'form-inline',
'onsubmit' => 'return check_minteacher()'
)); ?>
<div class="form-group col-md-3">
<?= $this->Form->input('bi_school_na', array(
'type' => 'text',
'onkeypress' => 'return isNumberKey(event)',
'label' => 'NA',
'placeholder' => 'NA',
'class' => 'form-control'
)); ?>
</div>
<?php
$options = array(
'label' => 'Submit',
'class' => 'btn btn-primary');
echo $this->Form->end($options);
?>
$this->Asc201516->set($this->request->data['Asc201516']);
if ($this->Asc201516->validates()) {
echo 'it validated logic';
exit();
} else {
$this->redirect(
array(
'controller' => 'asc201516s',
'action' => 'add', $semisid
)
);
}
public $validate = array(
'bi_school_na' => array(
'Numeric' => array(
'rule' => 'Numeric',
'required' => true,
'message' => 'numbers only',
'allowEmpty' => false
)
)
);
When I submit the form, logically it should not get submitted and print out the error message but the form gets submitted instead and validates the model inside controller which breaks the operation in controller.
Upvotes: 0
Views: 1086
Reputation: 1280
You have to check validation in your controller like
$this->Asc201516->set($this->request->data);
if($this->Asc201516->validates()){
$this->Asc201516->save($this->request->data);
}else{
$this->set("semisid",$semisid);
$this->render("Asc201516s/add");
}
You will have your ID
there in variable $semisid
, or you can set data in $this->request->data = $this->Asc201516->findById($semisid);
Upvotes: 1