Reputation: 65
I'm trying to write a program that finds the largest and smallest of 10 numbers.
To use my program, you must use the command line argument -l then numbers to determine largest number, the same for the command -s for smallest numbers.
However, when I don't enter a command at all, and just try to run the program, I receive a segmentation fault. Not sure where I went wrong.
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main(int argc, char* argv[])
{
int i;
int min,max,num;
char *argv1 = argv[1];
char *small = "-s";
char *large = "-l";
min=max=0;
if (0==strcmp(argv1, small))
{
for (i=2; i<argc; i++)
{
num=atoi(argv[i]);
if(i==2)
{
min=num;
}
else
{
if(min>num)min=num;
}
}
printf("The smallest number is %d\n",min);
}
else if (0==strcmp(argv1, large))
{
for (i=2; i<argc; i++)
{
num=atoi(argv[i]);
if(i==2)
{
max=num;
}
else
{
if(max<num)max=num;
}
}
printf("The largest number is %d\n",max);
}
else
{
printf("Invalid option");
}
return 0;
}
Upvotes: 0
Views: 7850
Reputation: 48
You're setting char *argv1 = argv[1];
without first checking argc
to see how many arguments were passed. This will cause a segfault when you later do if (0==strcmp(argv1, small))
because argv1
isn't pointing at a string like you are expecting it to.
To fix it, just check argc
before you start comparing argv1
with anything:
if (argc == 1)
{
printf("Error: -s or -l required\n");
exit(1);
}
Upvotes: 1
Reputation: 75062
Check the number of arguments before accessing to arguments.
int main(int argc, char* argv[])
{
int i;
int min,max,num;
char *argv1 = argv[1];
char *small = "-s";
char *large = "-l";
/* add from here */
if(argc < 2)
{
fprintf(stderr, "Usage: %s command numbers...\n", argc > 0 ? argv[0] : "");
return 1;
}
/* add until here */
min=max=0;
Upvotes: 3