CODEWITHSUNDEEP
python
Alan Robinson
Alan Robinson

Reputation: 69

Expected an indented block - driving me mad

choice = '' #Initialise choice to blank so will enter loop
print('MAIN MENU')             #---
print('-----------')           #--
print('1) Encrypt a message')  #- Display main menu
print('2) Decrypt a message')  #--
print('3) Exit')               #---
while choice not in ['1','2','3']:
    choice = input('Please choose 1,2 or 3 ')#Get user's choice
    if choice == "1":
        #encrypt() Call encrypt function
    elif choice == '2':
        # decrypt() Call decrypt function
    else:
        sys.exit() #Exit the program

Why is this happening no matter what indentation I try I still get the error! I have looked at other responses but none seem to help - I am sure it is trivial but I have tried loads of configurations but none work

Upvotes: 2

Views: 55

Answers (2)

AlokThakur
AlokThakur

Reputation: 3741

You can't have empty if or else block, 

while choice not in ['1','2','3']:
    choice = input('Please choose 1,2 or 3 ')#Get user's choice
    if choice == "1":
        pass
    elif choice == '2':
        pass
    else:
        sys.exit() #Exit the program

Upvotes: 3

interjay
interjay

Reputation: 110118

After a block statement like if and elif, you must have at least one indented line. Comments do not count, so there are no indented lines here:

if choice == "1":
    #encrypt() Call encrypt function
elif choice == '2':
    # decrypt() Call decrypt function

You can use a pass statement if you don't want to do anything in the block:

if choice == "1":
    pass #encrypt() Call encrypt function
elif choice == '2':
    pass #decrypt() Call decrypt function

Upvotes: 5

Related Questions