Reputation: 8151
In a Umbraco 7 solution, i have a Tags Content picker on all pages. Pages can with this, set tags on each page.
I then want to get alle pages, within the intire site, that has, lets say tag 111 (id, not name).
I have tried with:
var ids = Model.MacroParameters["tags"]; //the tags to show
CurrentPage.AncestorOrSelf(1).Descendants().Where(x => ids.Contains(x.tags.ToString()));
But that gives me the error:
Cannot use a lambda expression as an argument to a dynamically dispatched operation without first casting it to a delegate or expression tree type
Whats the correct way?
Upvotes: 0
Views: 323
Reputation: 146
Always try to avoid using Descendants, especially on the root node. To get the tags for a property:
ApplicationContext.Current.Services.TagService.GetTagsForProperty(Model.Content.Id, "propertyname")
To find content with a specific tag:
ApplicationContext.Current.Services.TagService.GetTaggedContentByTag("tag")
Upvotes: 0
Reputation: 4450
You have a few options, depending on whether you prefer a dynamic or strongly typed view model.
Strongly Typed API
Umbraco.TypedContentAtRoot().Descendants().Where(x => x.tags.Contains(ids));
Dynamic API
Umbraco.ContentAtRoot().Descendants().Where("tags.Contains(@0)", ids);
Please note that the Contains statement may give you inconsistent results, as the tags property seems to be returning a comma separated list. In that case you can try splitting the string or install the Core Property Value Converters package and get the tags as IEnumerable<IPublishedContent>
Upvotes: 1
Reputation: 8151
Solved it with;
Umbraco.Content(rootId).Descendants().Where("tags.Contains(@0)", ids);
Upvotes: 1