CODEWITHSUNDEEP
javapython-3.xhadoopapache-sparkpyspark
benSooraj
benSooraj

Reputation: 465

Reading large number of Excel files into Apache Spark

I have 100 Excel (*.xlsx) files stored in HDFS. The 100 *.xlsx files are organized into 10 directories, as shown below:

/user/cloudera/raw_data/dataPoint1/dataPoint.xlsx
/user/cloudera/raw_data/dataPoint2/dataPoint.xlsx
...
..
.
/user/cloudera/raw_data/dataPoint10/dataPoint.xlsx

Reading in one of *.xlsx files from above using 

rawData = sc.textFile("/user/cloudera/raw_data/dataPoint1/dataPoint.xlsx")

threw gibberish data!

One obvious suggestion I received was to use the Gnumeric spreadsheet application's command-line utility called ssconvert:

$ ssconvert dataPoint.xlsx dataPoint.csv

and then dump it into the HDFS, so I can read the *.csv file directly. But that is not what I am trying to solve or is the requirement.

Solutions in Python (preferable) and Java would be appreciated. I am a rookie, so a detailed walkthrough would be really helpful.

Thanks in advance.

Upvotes: 3

Views: 9159

Answers (4)

Iurii Ant
Iurii Ant

Reputation: 1025

You can use Spark Excel Library for converting xlsx files to DataFrames directly. See this answer with a detailed example.

As of version 0.8.4, the library does not support streaming and loads all the source rows into memory for conversion.

Upvotes: 1

Jörn Franke
Jörn Franke

Reputation: 186

You can try the HadoopOffice library: https://github.com/ZuInnoTe/hadoopoffice/wiki

Works with Spark and if you can use the Spark2 data source API you can use also Python. If you cannot use the Spark2 data source API then you can use the standard Spark APIs for reading/writing files using a HadoopFile Format provided by the HadoopOffice library.

Upvotes: 0

Kirupa
Kirupa

Reputation: 73

Use the following code to read excel files in Spark directly from HDFS using Hadoop FileSystem API. However you have to implement Apache POI API to parse the data

import org.apache.spark.SparkContext
import org.apache.spark.SparkContext._
import org.apache.spark.SparkConf
import java.util.Date
import scala.io.Source
import java.io.{ InputStream, FileInputStream, File }
import org.apache.poi.hssf.usermodel.HSSFWorkbook
import org.apache.poi.ss.usermodel.{ Cell, Row, Workbook, Sheet }
import org.apache.poi.xssf.usermodel._
import scala.collection.JavaConversions._
import org.apache.poi.ss.usermodel.WorkbookFactory
import org.apache.hadoop.conf.Configuration;
import org.apache.hadoop.fs.FileSystem;
import org.apache.hadoop.fs.FSDataInputStream;
import org.apache.hadoop.fs.FSDataOutputStream;
import org.apache.hadoop.fs.Path;
import java.net._

object Excel {
  def main(arr: Array[String]) {
    val conf = new SparkConf().setAppName("Excel-read-write").setMaster("local[2]")
    val sc = new SparkContext(conf)
    val fs = FileSystem.get(URI.create("hdfs://localhost:9000/user/files/timetable.xlsx"),new Configuration());
    val path=  new Path("hdfs://localhost:9000/user/files/timetable.xlsx");
    val InputStream = fs.open(path)
    read(InputStream)
  }
  def read(in:InputStream)={

  }
}

read(in:InputStream) method is where you implement Apache POI API to parse the data.

Upvotes: 2

Manish Mishra
Manish Mishra

Reputation: 848

If you are willing to build yourself a custom XLSX to CSV Converter, The Apache POI Event API would be Ideal for this. This API is suitable for Spreadsheets with large memory footprints. Look out what is it about here. Here is an example XSLX processing with the XSSF Event code

Upvotes: 0

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