CODEWITHSUNDEEP
pythonemailurlhyperlinkimaplib
Mike
Mike

Reputation: 207

How do I retrieve a hyperlink URL from email within python?

I have the following code to get an HTML email as a email.Message object but am unsure how to proceed from here to find the url of the hyperlink given its display name. I have located the url in the payload(0). In addition the email is a href=3D so it doesnt work if i just copy the link and paste into a browser.

import sys
import imaplib 
import getpass
import email
import datetime
import email


M = imaplib.IMAP4_SSL('imap.gmail.com')
M.login('[email protected]','password123')

rv,boxes = M.list()
rv,boxes = M.select('Inbox/Test1')

rv, data = M.search(None, 'ALL')
typ, msg_data = M.fetch('1', '(RFC822)')

msg = email.message_from_string(msg_data[0][1])

url_name = 'Click Here'
html_text = msg.get_payload(0)

Upvotes: 2

Views: 5934

Answers (1)

Mike
Mike

Reputation: 207

this will show all href in the message...one can update the parseLinks class to choice their individual string they are interested in. 

import imaplib 
import email
import quopri
import HTMLParser

class parseLinks(HTMLParser.HTMLParser):
    def handle_starttag(self, tag, attrs):
        global global_futures_fair_value
        if tag == 'a':
            for name, value in attrs:
                if name == 'href':
                    print name
                    print value


M = imaplib.IMAP4_SSL('imap.gmail.com')
M.login('[email protected]','password123')

M.select('Inbox/Test1')

rv, data = M.search(None, 'ALL')
typ, msg_data = M.fetch('1', '(RFC822)')

msg = email.message_from_string(msg_data[0][1])

url_name = 'Click Here'
html_text = msg.get_payload(0)

msg = str(msg.get_payload()[0])
msg = quopri.decodestring(msg)

linkParser = parseLinks()
linkParser.feed(msg)

Upvotes: 3

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