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pythonarraysnumpymultidimensional-array
David
David

Reputation: 1267

Iterating and selecting a specific array from a multidimensional array in Python

Imagine I have something like this:

 import numpy as np
 arra = np.arange(16).reshape(2, 2, 4)

which gives 

 array([[[0, 1, 2, 3],  
      [4, 5, 6, 7]],  
      [[8, 9, 10, 11],  
      [12, 13, 14, 15]]])

and I want to make a loop that runs along specific subarrays (in this case, I want to run along each 'column' of each 'matrix') and sum the result (that is, selecting 0 and 4 and summing them (4), selecting 1 and 5 and summing them (6), ..., selecting 3 and 7 and summing them (10), selecting 8 and 12 and summing them (20), ..., selecting 11 and 15 and summing them (26)).

I had thought doing that with the apparently natural: 

 for i in arra[i, j, k]:  
     for j in arra[i, j, k]:  
         for k in arra[i, j, k]:  
             sum...

The problem is that Python certainly doesn't allow to do what I want in this way. If it were a 2D array it would be easier as I know that the iterator first runs through the rows, so you can transpose to run along the columns, but for a multidimensional (3D in this case) array (N, M, P) with N, M, P >> 1, I was wondering how it could be done.

EDIT: This question has a continuation here: Choosing and iterating specific sub-arrays in multidimensional arrays in Python

Upvotes: 3

Views: 429

Answers (1)

Cleb
Cleb

Reputation: 25997

You can use map to get this done:

import numpy as np
arra = np.arange(16).reshape(2, 2, 4)

Then the command:

map(sum, arra)

gives you the desired output:

[array([ 4,  6,  8, 10]), array([20, 22, 24, 26])]

Alternatively, you can also use a list comprehension:

res = [sum(ai) for ai in arra]

Then res looks like this:

[array([ 4,  6,  8, 10]), array([20, 22, 24, 26])]

EDIT:

If you want to add identical rows - as you mentioned in the comments below this answer - you can do (using zip):

map(sum, zip(*arra))

which gives you the desired output:

[array([ 8, 10, 12, 14]), array([16, 18, 20, 22])]

For the sake of completeness also the list comprehension:

[sum(ai) for ai in zip(*arra)]

which gives you the same output.

Upvotes: 1

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