CODEWITHSUNDEEP
pythonweb-servicesrestpost
froadie
froadie

Reputation: 83153

Calling a REST service with Python

I have a REST service that I'm trying to call. It requires something similar to the following syntax:

http://someServerName:8080/projectName/service/serviceName/
      param1Name/param1/param2Name/param2

I have to connect to it using POST. I've tried reading up on it online (here and here, for example)... but this is my problem:

If I try using the HTTP get request method, by building my own path, like this:

BASE_PATH = "http://someServerName:8080/projectName/service/serviceName/"
urllib.urlopen(BASE_PATH + "param1/" + param1 + "/param2/" + param2)

it gives me an error saying that GET is not allowed.

If I try using the HTTP post request method, like this:

params = { "param1" : param1, "param2" : param2 }
urllib.urlopen(BASE_PATH, urllib.urlencode(params))

it returns a 404 error along with the message The requested resource () is not available. And when I debug this, it seems to be building the params into a query string ("param1=whatever&param2=whatever"...)

How can I use POST but pass the parameters delimited by slashes as it's expected? What am I doing wrong?

Upvotes: 3

Views: 11474

Answers (3)

froadie
froadie

Reputation: 83153

I know this is sort of unfair, but this is what ended up happening... The programmer in charge of the REST service changed it to use the &key=value syntax.

Upvotes: 5

carl
carl

Reputation: 50554

Something like this might work:

param1, param2 = urllib.quote_plus(param1), urllib.quote_plus(param2)
BASE_PATH = "http://someServerName:8080/projectName/service/serviceName/"
urllib.urlopen(BASE_PATH + "param1/" + param1 + "/param2/" + param2, " ")

The second argument to urlopen tells it to do a POST request, with empty data. The quote_plus allows you to escape special characters without being forced into the &key=value scheme.

Upvotes: 0

Jason Scheirer
Jason Scheirer

Reputation: 1698

  1. Use urllib2

  2. You're going to have to be clever; something like

    params = { "param1" : param1, "param2" : param2 }

    urllib2.urlopen(BASE_PATH + "?" + urllib.urlencode(params), " ")

    Might work.

Upvotes: 2

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