CODEWITHSUNDEEP
scalaclasscasejson4s
Swadeshi
Swadeshi

Reputation: 1672

json4s response to case class

I am getting this json response, how to create Scala Case Class for the page_views ??

"page_views": {
    "2015-12-30T21:30:00+05:30": 4,
    "2016-01-08T15:30:00+05:30": 25,
    "2016-01-13T11:30:00+05:30": 9,
    "2016-01-13T12:30:00+05:30": 8,
    "2016-01-14T10:30:00+05:30": 21,
    "2016-01-21T12:30:00+05:30": 19,
    "2016-01-21T17:30:00+05:30": 4,
    "2016-01-22T17:30:00+05:30": 2,
    "2016-02-02T10:30:00+05:30": 14,
    "2016-02-24T12:30:00+05:30": 11,
    "2016-02-26T09:30:00+05:30": 12
  },

Upvotes: 1

Views: 220

Answers (3)

Swadeshi
Swadeshi

Reputation: 1672

After many tries , I was able to make it work. I used a Map to bind to the JSON fields.

case class Test(page_views: Map[String, Int])

Upvotes: 1

pedrorijo91
pedrorijo91

Reputation: 7865

you may follow up this tutorial that covers how to parse json strings to your model. It also covers some usual transformations you may need to apply to convert from the json to your case class

but your case is kinda weird, shouldn't page_views contain/be an array? how can you process the page_views json object if you don't know which fields are in it?

Upvotes: 0

John K
John K

Reputation: 1285

First define what case class you want. Let's say it's something like case class PageView(date:myDateType,numberViews:Long). Then you don't fall in the basic case where the json you receive has the fields date and numberViews explicitly written, e.g {"date":"xxx","numberViews":123}. So using json4s it won't be enough to create a case class and let it do the rest, you will have to write a custom (de)serializer (they have an example here, search 'Serializer' on the page).

Upvotes: 1

Related Questions