Reputation: 55
I have a situation (on an embedded system) where I want call functions from another task. I found this method to do so http://www.drdobbs.com/elegant-function-call-wrappers/184401385 . But I what to do so with more arguments. Best case I have a solution where this is in the template to, but I have no clue how to realise that. Anyway, it is also possible to create two temples as shown below (in a small visual studio C++ test). Everything function fine, except the DeferCall2 call that give a compile time error. What mistake I made here?
#include "stdafx.h"
#include "stdlib.h"
#include "stdio.h"
class Functor
{
public:
virtual ~Functor() {}
virtual void operator()() = 0;
};
template< class CalleePtr, class MemFunPtr, class Parm1 >
class MemberFunctor1 : public Functor
{
public:
MemberFunctor1
(
const CalleePtr & pCallee,
const MemFunPtr & pFunction,
Parm1 aParm1
) :
pCallee(pCallee),
pFunction(pFunction),
aParm1(aParm1)
{
}
virtual void operator()()
{
if ((pCallee != NULL) &&
(pFunction != NULL))
{
((*pCallee).*pFunction)(aParm1);
}
}
private:
CalleePtr pCallee;
MemFunPtr pFunction;
Parm1 aParm1;
};
template< class CalleePtr, class MemFunPtr, class Parm1, class Parm2 >
class MemberFunctor2 : public Functor
{
public:
MemberFunctor2
(
const CalleePtr & pCallee,
const MemFunPtr & pFunction,
Parm1 aParm1,
Parm2 aParm2
) :
pCallee(pCallee),
pFunction(pFunction),
aParm1(aParm1),
aParm2(aParm2)
{
}
virtual void operator()()
{
if ((pCallee != NULL) &&
(pFunction != NULL))
{
((*pCallee).*pFunction)(aParm1, aParm2);
}
}
private:
CalleePtr pCallee;
MemFunPtr pFunction;
Parm1 aParm1;
Parm2 aParm2;
};
template< class CalleePtr, class Callee, class Ret, class Type1, class Parm1 >
inline Functor * DeferCall
(
const CalleePtr & pCallee,
Ret(Callee::*pFunction)(Type1),
const Parm1 & rParm1
)
{
return new
MemberFunctor1< CalleePtr,
Ret(Callee::*)(Type1), Parm1 >
(pCallee, pFunction, rParm1);
}
template< class CalleePtr, class Callee, class Ret, class Type1, class Parm1, class Parm2>
Functor * DeferCall2
(
const CalleePtr & pCallee,
Ret(Callee::*pFunction)(Type1),
const Parm1 & rParm1,
const Parm2 & rParm2
)
{
return new
MemberFunctor2< CalleePtr,
Ret(Callee::*)(Type1), Parm1, Parm2 >
(pCallee, pFunction, rParm1, rParm2);
}
class TestObj
{
public:
void test1 (int a)
{
printf("test 1 a=%d\r\n", a);
}
void test2 (int a, int b)
{
printf("test 2 a=%d, b=%d\r\n", a, b);
}
void test (void)
{
Functor * pCall = DeferCall(this, &TestObj::test1, 3);
Functor * pCall1 = new MemberFunctor1 < TestObj *, void (TestObj::*)(int), int >(this, &TestObj::test1, 6);
Functor * pCall2 = new MemberFunctor2 < TestObj *, void (TestObj::*)(int, int), int, int >(this, &TestObj::test2, 4, 5);
Functor * pCall3 = DeferCall2(this, &TestObj::test2, 3, 3); // Compile time error.
if (pCall)
(*pCall)();
if (pCall1)
(*pCall1)();
if (pCall2)
(*pCall2)();
if (pCall3)
(*pCall3)();
delete pCall;
delete pCall1;
delete pCall2;
delete pCall3;
}
};
int _tmain(int argc, _TCHAR* argv[])
{
TestObj *obj = new TestObj();
obj->test();
delete obj;
return 0;
}
Upvotes: 0
Views: 63
Reputation: 4432
You forgot the second int parameter in the function:
template <class CalleePtr, class Callee, class Ret, class Type1, class Parm1, class Parm2>
Functor* DeferCall2(const CalleePtr& pCallee, Ret (Callee::*pFunction)(Type1, Type1), const Parm1& rParm1,
const Parm2& rParm2) {
return new MemberFunctor2<CalleePtr, Ret (Callee::*)(Type1, Type1), Parm1, Parm2>(pCallee, pFunction, rParm1, rParm2);
}
Changes are here:
Ret (Callee::*pFunction)(Type1, Type1)
^^^^^^^
in the two places that appear Or add another template parameter if the second type is not always same as first.
The calling functors has two ints: void (TestObj::*)(int, int)
Upvotes: 1
Reputation: 303487
You are calling:
DeferCall2(this, &TestObj::test2, 3, 3);
where &TestObj::test2
has type void (TestObject::*)(int, int)
. The signature of DeferCall2
has unnecessarily many template parameters, but the second argument it takes has type:
Ret(Callee::*pFunction)(Type1)
That is, a pointer to non-cv-qualified, non-variadic member function that takes one argument. Hence the deduction failure. You're missing a second type there.
Note that you're effectively just re-implementing std::bind
:
auto call3 = std::bind(this, &TestObj::test2, 3, 3);
call3();
Upvotes: 0