CODEWITHSUNDEEP
javascriptjquery
Bharti Sharma
Bharti Sharma

Reputation: 3

finding index of object in array in js accordign to value in array

I have my array like callsData[] which contains objects like following:

{
  "caller_id": "110",
  "Channel": "SIP/Kam-SBC-0000001c",
  "AccountCode": "1004",
  "Server": "192.168.1.36",
  "Callee": "109",
  "connected_line": "109",
  "Uniqueid": "145712272845",
  "DestChannel": "SIP/Kam-SBC-0000001d",
  "DestUniqueid": ["3432423423423","123123123","312321312"]
}

I want to find index of object where my value 3432423423423 is present in the DestUniqueid array.

Upvotes: 0

Views: 84

Answers (5)

Scott Marcus
Scott Marcus

Reputation: 65873

Loop over the main array and upon each iteration, check the DestUniqueid property to see if it contains the value you seek:

function findIndex(valToFind){
 for(var i = 0; i < callsData.length; ++i){
   if(callsData[i].DestUniqueid.indexOf(valToFind) >= 0) {
       return i;
   }
 }
}

Upvotes: 0

isvforall
isvforall

Reputation: 8926

Using Array#find function:

var index;

callsData.find(function(el, i) {
    if (el.DestUniqueid.indexOf('3432423423423') != -1) {
        index = i;
        return true;
    }
})

console.log(index); // index that you need

Also you can use Array#filter function to get all elements with DestUniqueid that you need:

var arr = callsData.filter(function(el){
     return el.DestUniqueid.indexOf('3432423423423') != -1;
});

console.log(arr); // array of callsData with your DestUniqueid

Upvotes: 0

Cripto
Cripto

Reputation: 3751

var x = {
  "caller_id": "110",
  "Channel": "SIP/Kam-SBC-0000001c",
  "AccountCode": "1004",
  "Server": "192.168.1.36",
  "Callee": "109",
  "connected_line": "109",
  "Uniqueid": "145712272845",
  "DestChannel": "SIP/Kam-SBC-0000001d",
  "DestUniqueid": ["3432423423423","123123123","312321312"]
}

x.DestUniqueid.indexOf("3432423423423")
> 0
x.DestUniqueid.indexOf("312321312")
> 2

So you could just call index of in a function 

var findIndex = function(obj, myVar){
   return obj.DestUniqueid.indexOf(myVar)
}

and call it like:

findIndex(x, "312321312")
>2

Upvotes: 0

Tate Thurston
Tate Thurston

Reputation: 4660

Here is a simple function to accomplish that in linear time.

How large is the array? Is it sorted in any way?

function findIndex (array, target) {
 for (var i = 0; i < array.length; i++){
   if (array[i].DestUniqueid) === target){
     return i;
   }
   return null;
 }
}

Upvotes: 0

Rajaprabhu Aravindasamy
Rajaprabhu Aravindasamy

Reputation: 67217

Try to write a simple for loop,

for(var i=0;i<callsData.length;i++){
  if(callsData[i].DestUniqueid.indexOf("3432423423423") > -1)
  break;
}

console.log(i + " is the index of element with value 3432423423423");

If you want it as a function then just write like,

function getIndex(val){
 for(var i=0;i<callsData.length;i++){
  if(callsData[i].DestUniqueid.indexOf(val) > -1)
   break;
 }
 return i;
}

console.log(getIndex("3432423423423") + " is the index of element with value 3432423423423");

DEMO

Upvotes: 1

Related Questions