Reputation: 299
I have created a form in html and I would like that the dataentered in the form is sent to a mysql database in XAMMP. I created the database, the table and the connectivity.php file that manages the connection to the database and data entry, but when I try I get the following error:
"Fatal error: Uncaught Error: Call to undefined function mysql_connect() in C:\xampp\htdocs\example\connectivity.php:8 Stack trace: #0 {main} thrown in C:\xampp\htdocs\example\connectivity.php on line 8"
I post all the code that I wrote. Does anyone know where I'm wrong?
here is the form index.html
<!DOCTYPE HTML>
<html>
<head>
<title>Contact Us</title>
<link rel="stylesheet" type="text/css" href="style.css">
<?php include("connectivity.php"); ?>
</head>
<body>
<div id="contact">
<h3>Contact Us For Any Query</h3>
<form method="POST" action="connectivity.php">
Name
<br>
<input type="text" name="name">
<br> Email
<br>
<input type="text" name="email">
<br> Message
<br>
<textarea rows="10" cols="50" maxlength="100" name="message"></textarea>
<br>
<input type="submit" value="Send Message">
</form>
</div>
</body>
</html>
Then the code used to define database and the table:
CREATE DATABASE practice;
USE practice;
CREATE TABLE contact
(
contactID INT(9) NOT NULL auto_increment,
contactName VARCHAR(40) NOT NULL,
contactEmail VARCHAR(40) NOT NULL,
message VARCHAR(250) NOT NULL,
PRIMARY KEY(contactID)
);
Finally the connectivity.php file:
<?php
//connecting to the database
define('DB_HOST', 'localhost');
define('DB_NAME', 'practice');
define('DB_USER','root');
define('DB_PASSWORD','');
$con=mysql_connect(DB_HOST, DB_USER, DB_PASSWORD) or die("Failed to connect to MySQL: " . mysql_error());
$db=mysql_select_db(DB_NAME,$con) or die("Failed to connect to MySQL: " . mysql_error());
//inserting Record to the database
$name = $_POST['name'];
$email = $_POST['email'];
$message = $_POST['message'];
$query = "INSERT INTO contact(contactName,contactEmail,message)VALUES('$name','$email','$message')";
$result = mysql_query($query);
if($result)
{
echo "Successfully updated database";
}
else
{
die('Error: '.mysql_error($con));
}
mysql_close($con);
?>
P.S: I installed the latest version of XAMMP (5.6.15)
$con=mysqli_connect(DB_HOST, DB_USER, DB_PASSWORD,##TABLE NAME##) or die("Failed to connect to MySQL: " . mysql_error());
$query = "INSERT INTO contact(contactName,contactEmail,message)VALUES('$name','$email','$message')"; $result = mysqli_query($con,$query);
Upvotes: 1
Views: 1716
Reputation: 2869
If you are using one of the latest version of xampp
therefore you have to use PDO or MySQLi .
Your have to change your codes to something like this.
Your connectivity page
<?php
$db = new PDO('mysql:host=localhost;dbname=practice;charset=utf8',
'root',
'',
array(PDO::ATTR_EMULATE_PREPARES => false,
PDO::ATTR_ERRMODE => PDO::ERRMODE_EXCEPTION));
?>
<?php
if (isset($_POST['name'])) {
$name = $_POST['name'];
$email = $_POST['email'];
$message = $_POST['message'];
$stmt = $db->prepare("INSERT INTO `contact` (contactName,contactEmail,message)
VALUES (:name, :email, :message)");
$stmt->bindParam(':name', $name);
$stmt->bindParam(':email', $email);
$stmt->bindParam(':message', $message);
$stmt->execute();
echo 'added';
}
?>
Your home page
<!DOCTYPE HTML>
<html>
<head>
<title>Contact Us</title>
<link rel="stylesheet" type="text/css" href="style.css">
</head>
<body>
<div id="contact">
<h3>Contact Us For Any Query</h3>
<form method="POST" action="connectivity.php">
Name
<br>
<input type="text" name="name">
<br> Email
<br>
<input type="text" name="email">
<br> Message
<br>
<textarea rows="10" cols="50" maxlength="100" name="message"></textarea>
<br>
<input type="submit" value="Send Message">
</form>
</div>
</body>
</html>
Hope this helps
Upvotes: 1
Reputation: 1667
Firts you see your phpinfo:
<?php
phpinfo();
?>
Then see in here , php_mysql
is enabled or disabled?
If there not php_mysql
, change php.ini
file:
Uncomment extension=php_mysql.dll
Upvotes: 1