CODEWITHSUNDEEP
phpmysqlsql
dark_illusion_909099
dark_illusion_909099

Reputation: 1099

How do I get the column name of a foreign key reference in PHP

I have got two tables: category and quiz

In category I have : category_id | category_name |

In quiz I have : quiz_id | quiz_name | quiz_category_id| quiz_duration

As you can notice, quiz_category_id is a FOREIGN KEY reference.

This is the code I have so far: 

<table>
   <thread>
      <tr>
         <th>quiz name</th>
         <th>quiz category</th>
         <th>quiz duration</th>
     </tr>
   </thread>
     <tbody>
        <?php foreach (get_all_exam() as $r) { ?>
         <tr>
             <td><?php echo $r['quiz_name'] ?></td>
             <td><?php echo $r['quiz_category_id'] ?></td> // I am getting the id value not the name
             <td><?php echo $r['quiz_duration'] ?></td>
        </tr>
        <?php } ?>
     </tbody>
</table>

get_all_exam() is a function and here it is: This is where I do the sql query

function get_all_exam () {
    $data = array();

    $result = mysql_query("SELECT * FROM `quiz`");

    while ($row = mysql_fetch_assoc($result)) {
        $data [] = $row;
    }

    return $data;
}

So at the minute, it just prints out for example;

|quiz name| |quiz category| |quiz duration|

|practice ex | |23| |5 minutes|

Instead of it saying 23 I want it so that it looks up on the corresponding table to get the name

Thanks

Upvotes: 0

Views: 389

Answers (1)

Muhammed
Muhammed

Reputation: 1612

SELECT quiz.quiz_name, category.catagory_name, quiz.quiz_duration 
FROM quiz LEFT JOIN category 
ON (quiz.quiz_category_id = category.category_id)

Inside select statement, select what you want, you could also say SELECT quiz.*, category.*, but be careful if you have same field names, you might want to retrieve some with AS.

LEFT JOIN means - always show from left table, even if there is no value in the right table; thus, it will show quiz_id, even if there is no corresponding category_id. RIGHT JOIN will do just the opposite.

Upvotes: 1

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