CODEWITHSUNDEEP
scalacsvapache-sparkrdd
DK2
DK2

Reputation: 661

Make RDD from LIST[Row] In scala(in spark)

I'm making some code with scala & spark and want to make CSV file from RDD or LIST[Row].

I wanted to process 'ListRDD' data parellel so I thouth output data would be more than one file.

val conf = new SparkConf().setAppName("Csv Application").setMaster("local[2]")
val sc = new SparkContext(conf)
val sqlContext = new SQLContext(sc)
val logFile = "data.csv "
val rawdf = sqlContext.read.format("com.databricks.spark.csv")....
val rowRDD = rawdf.map { row =>
  Row(
    row.getAs( myMap.ID).toString,
    row.getAs( myMap.Dept)
    .....
  )
}
 val df = sqlContext.createDataFrame(rowRDD, mySchema)
val MapRDD = df.map { x => (x.getAs[String](myMap.ID), List(x)) }
val ListRDD = MapRDD.reduceByKey { (a: List[Row], b: List[Row]) => List(a, b).flatten }

myClass.myFunction( ListRDD)

in myClass..

def myFunction(ListRDD: RDD[(String, List[Row])]) = {
    var rows: RDD[Row]
    ListRDD.foreach( row => { 
        rows.add? gather? ( make(row._2)) // make( row._2) will return List[Row]
    })
    rows.saveAsFile(" path") // it's my final goal
  }

def make( list: List[Row]) : List[Row] = {
    data processing from List[Row]
}

I tried to make RDD data from List by sc.parallelize( list) BUT somehow nothing works. anyidea to make RDD type data from make function.

Upvotes: 1

Views: 1084

Answers (1)

Jay Vignesh
Jay Vignesh

Reputation: 179

If you want to make an RDD from a List[Row], here is a way to do so

//Assuming list is your List[Row]
val newRDD: RDD[Object] = sc.makeRDD(list.toArray());

Upvotes: 0

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