Reputation: 3587
I have a dataframe with two columns one of which (called dist) is a dense vector. How can I convert it back into an array column of integers.
+---+-----+
| id| dist|
+---+-----+
|1.0|[2.0]|
|2.0|[4.0]|
|3.0|[6.0]|
|4.0|[8.0]|
+---+-----+
I tried using several variants of the following udf but it returns a type mismatch error
val toInt4 = udf[Int, Vector]({ (a) => (a)})
val result = df.withColumn("dist", toDf4(df("dist"))).select("dist")
Upvotes: 6
Views: 13689
Reputation: 540
I struggled for a while to get the answer from @ThomasLuechtefeld working. But was running into this very frustrating error:
org.apache.spark.sql.AnalysisException: cannot resolve 'UDF(features_scaled)' due to data type mismatch: argument 1 requires vector type, however, '`features_scaled`' is of vector type.
Turns out I needed to import DenseVector from the ml package instead of the mllib package.
So this worked for me:
import org.apache.spark.ml.linalg.DenseVector
import org.apache.spark.sql.functions._
val vectorToColumn = udf{ (x:DenseVector, index: Int) => x(index) }
myDataframe.withColumn("clusters_scaled",vectorToColumn(col("features_scaled"),lit(0)))
Yes, the only difference is that first line. This should absolutely be a comment, but I don't have the reputation. Sorry!
Upvotes: 10
Reputation: 1456
In spark 2.0 you can do something like:
import org.apache.spark.mllib.linalg.DenseVector
import org.apache.spark.sql.functions.udf
val vectorHead = udf{ x:DenseVector => x(0) }
df.withColumn("firstValue", vectorHead(df("vectorColumn")))
Upvotes: 3
Reputation: 27455
I think it's easiest to do it by going to the RDD API and then back.
import org.apache.spark.mllib.linalg.DenseVector
import org.apache.spark.sql.DataFrame
import org.apache.spark.rdd.RDD
import sqlContext._
// The original data.
val input: DataFrame =
sc.parallelize(1 to 4)
.map(i => i.toDouble -> new DenseVector(Array(i.toDouble * 2)))
.toDF("id", "dist")
// Turn it into an RDD for manipulation.
val inputRDD: RDD[(Double, DenseVector)] =
input.map(row => row.getAs[Double]("id") -> row.getAs[DenseVector]("dist"))
// Change the DenseVector into an integer array.
val outputRDD: RDD[(Double, Array[Int])] =
inputRDD.mapValues(_.toArray.map(_.toInt))
// Go back to a DataFrame.
val output = outputRDD.toDF("id", "dist")
output.show
You get:
+---+----+
| id|dist|
+---+----+
|1.0| [2]|
|2.0| [4]|
|3.0| [6]|
|4.0| [8]|
+---+----+
Upvotes: 5