CODEWITHSUNDEEP
javaandroid
Freedi
Freedi

Reputation: 31

What's the error here?

int i = 10000;
Integer.toBinaryString(i);

How can I make the Integer.toBinaryString method return leading zeroes as well? For example, for i = 1000, I want 00000000000000000000001111101000 to appear, not 1111101000.

Upvotes: 0

Views: 60

Answers (1)

John Hascall
John Hascall

Reputation: 9416

If you want to left pad the result with zeros, you could do:

String raw = Integer.toBinaryString(i);
String padded = "0000000000000000".substring(raw.length()) + raw;

Here I chose a width of 16 digits, you can adjust the width by the number of zeros in the string.

Note, if it is possible that i > 2^16 - 1 then this will fail and you'll need to protect against that (32 zeros would be one approach).

EDIT

Here's a more complicated version which formats to the smallest of 8, 16, 24, or 32 bits which will contain the result:

public class pad {
    public static String pbi ( int i ) {
        String raw = Integer.toBinaryString(i);
        int n = raw.length();
        String zeros;
        switch ((n-1)/8) {
            case 0: zeros = "00000000";                         break;
            case 1: zeros = "0000000000000000";                 break;
            case 2: zeros = "000000000000000000000000";         break;
            case 3: zeros = "00000000000000000000000000000000"; break;
            default: return raw;
        }
        return zeros.substring(n) + raw;
    }

    public static void main ( String[] args ) {
        Scanner s = new Scanner(System.in);
        System.out.print("Enter an integer : ");
        int i = s.nextInt();
        System.out.println( pbi( i ) );
    }
}

Upvotes: 1

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