CODEWITHSUNDEEP
pythonlist
Joey
Joey

Reputation: 25

How to create a double digit integer list from a single digit integer list?

l=[1,4,5,6,3,2,4,0]

I want the to out come to be 

newlist=[14,56,32,40]

I have tried 

for i in l[::2]:
   newlist.append(i)

what to do

Upvotes: 2

Views: 677

Answers (3)

EduardoCMB
EduardoCMB

Reputation: 494

lst = [1,4,5,6,3,2,4,0,1]
length = len(lst)
newList = [i*10+j for i,j in zip(lst[::2],lst[1::2])] 
if length % 2 == 1:
    newList.append(lst[-1]*10)

print newList

Output:

[14, 56, 32, 40, 10]

Upvotes: 0

Kasravnd
Kasravnd

Reputation: 107297

You can use zip() function within a list comprehension:

>>> lst = [1,4,5,6,3,2,4,0]
>>> [i*10+j for i,j in zip(lst[0::2],lst[1::2])]
[14, 56, 32, 40]

As a more general approach for covering the list with odd number of items you can use itertools.izip_longest (in python 3.X itertools.zip_longest) : by passing the 0 as fillvalue argument:

>>> lst=[1,4,5,6,3,2,4]
>>> 
>>> from itertools import izip_longest
>>> [i*10+j for i,j in izip_longest(lst[0::2],lst[1::2], fillvalue=0)]
[14, 56, 32, 40]

Upvotes: 4

DevLounge
DevLounge

Reputation: 8437

An alternate solution, just for fun

lst = [1,4,5,6,3,2,4,0]
it = iter(lst)
for i in it:
  num = int(str(i) + str(next(it)))
  print num

Upvotes: 1

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