Reputation: 91
How do I handle this issue
clear all; close all; clc;
r = 0:5;
zeta = 0:0.1:1;
for i = 1:size(zeta(:))
for j = 1:size(r(:))
X(i,j) = sqrt((1+(2*zeta(i)*r(j))^2)/((1-r(j)^2)^2+ (2*zeta(i)*r(j))^2));
end
plot(r,X);
xlabel('r = \omega/\omega_n');
ylabel('M = \frac{X}{Y}');
hold all
grid
[~,~,~,current_entries] = legend;
legend([current_entries {sprintf('\zeta = %i',zeta(i))}]);
end
figure
plot(r,X)
grid
The hold all
command doesn't seem to be working properly. What can I do to fix this?
Upvotes: 1
Views: 421
Reputation: 65460
You will want to set the DisplayName
property of the plot. Then when you create the legend
, the labels will automatically be populated.
plot(r, X, 'DisplayName', 'name')
Also, the string that you were passing to sprintf
for your legends needs to be escaped becuase sprintf
thinks that \z
is a control character.
plot(r, X, 'DisplayName', sprintf('\\zeta = %0.1f',zeta(k)))
Also, hold on
is recommended over hold all
. Also, it is best practice to specify the axes handle when calling hold
to ensure that it is applied to the current axes.
hold(hax, 'on')
So if we incorporate these changes into your plotting code (along with @R.Falque's idea to use semilogy
)
r = 0:0.001:5;
zeta = 0:0.1:1;
hax = axes();
colors = hsv(numel(zeta));
for k = 1:numel(zeta)
X = sqrt((1 + (2 * zeta(k) * r).^2) ./ ((1-r.^2).^2+ (2*zeta(k)*r).^2));
semilogy(r, X, ...
'DisplayName', sprintf('\\zeta = %0.1f',zeta(k)), ...
'Color', colors(k,:));
hold(hax, 'on')
end
grid(hax, 'on')
xlabel(hax, 'r = \omega/\omega_n', 'Interpreter', 'tex');
ylabel(hax, 'M = $\displaystyle\frac{X}{Y}$', 'Interpreter', 'latex');
L = legend('show');
Upvotes: 2
Reputation: 944
You can also use cells array as follow:
clear all; close all; clc;
r = 0:0.001:5;
zeta = 0:0.1:1;
figure;
for i = 1:length(zeta)
for j = 1:length(r)
X(j) = sqrt((1+(2*zeta(i)*r(j))^2)/((1-r(j)^2)^2+ (2*zeta(i)*r(j))^2));
end
semilogy(r,X);
hold on
legend_string{i} = ['\zeta = ', num2str(zeta(i))];
end
hold off
grid
xlabel('r = \omega/\omega_n');
ylabel('M = $\frac{X}{Y}$','Interpreter', 'Latex');
legend(legend_string);
Note that you have an error in the X
definition (corrected from X(i,j)
to X(j)
).
Upvotes: 1