CODEWITHSUNDEEP
javabatch-file
onlycparra
onlycparra

Reputation: 775

Issue running a java program from a batch script

I have a problem with a batch script that runs a java program, here some key lines of the script:

exeFinder="java -client -classpath './classes:./lib/javacsv.jar' -Xmx7200m Finder.Main ";
runFinder() {
    cleanFolders;
    $exeFinder $1 $2 $3 > $4;
}
dbName=$1;
k=$2;
n=$3;
outFile="simple_tester-out.log";

runFinder $dbName $k $n $outFile;

I run the script with its arguments: ./myScript.sh testing_7x8.csv 7 8
And I get this:

Error: Could not find or load main class Finder.Main

It looks like a java problem, so I change the line $exeFinder $1 $2 $3 > $4; for echo "$exeFinder $1 $2 $3 > $4"; to get my execution line:

java -client -classpath './classes:./lib/javacsv.jar' -Xmx7200m Finder.Main  testing_7x8.csv 7 8 > simple_tester-out.log

And it works like a charm! So I don't know what is happening.

I have checked some questions like this and this, but I can't see anything useful for me.

Thanks for your time, guys

Upvotes: 0

Views: 80

Answers (2)

onlycparra
onlycparra

Reputation: 775

It was a little problem with the simple quotes in the execution variable, so instead of:

"java -client -classpath './classes:./lib/javacsv.jar' -Xmx7200m Finder.Main "

it must be:

"java -client -classpath ./classes:./lib/javacsv.jar -Xmx7200m Finder.Main "

It is probably something related with bash and how it works, I don't know enough to explain why this happens, but that change solved the problem.

Upvotes: 1

Sam Jones
Sam Jones

Reputation: 1548

Try sh $exeFinder $1 $2 $3 > $4;

In my testing, I was unable to directly execute a command in a variable, but I could pass it to sh.

Upvotes: 0

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