Reputation: 719
I found some code to display a Mandelbrot set in java, this one has a turqoise colour theme and I was wondering how to change this to another colour, for example a red colour theme. Here is the code:
import java.awt.Graphics;
import java.awt.image.BufferedImage;
import javax.swing.JFrame;
public class Mandelbrot extends JFrame {
private final int MAX_ITER = 570;
private final double ZOOM = 150;
private BufferedImage I;
private double zx, zy, cX, cY, tmp;
public Mandelbrot() {
super("Mandelbrot Set");
setBounds(100, 100, 800, 600);
setResizable(false);
setDefaultCloseOperation(EXIT_ON_CLOSE);
I = new BufferedImage(getWidth(), getHeight(), BufferedImage.TYPE_INT_RGB);
for (int y = 0; y < getHeight(); y++) {
for (int x = 0; x < getWidth(); x++) {
zx = zy = 0;
cX = (x - 400) / ZOOM;
cY = (y - 300) / ZOOM;
int iter = MAX_ITER;
while (zx * zx + zy * zy < 4 && iter > 0) {
tmp = zx * zx - zy * zy + cX;
zy = 2.0 * zx * zy + cY;
zx = tmp;
iter--;
}
I.setRGB(x, y, iter | (iter << 8));
}
}
}
@Override
public void paint(Graphics g) {
g.drawImage(I, 0, 0, this);
}
public static void main(String[] args) {
new Mandelbrot().setVisible(true);
}
}
The hex code for red is #FF0000 and the rbg decimal code is (255,0,0) if that helps.
Thanks for your time.
Upvotes: 1
Views: 242
Reputation: 2682
The essense of your code (in coloring) is this
I.setRGB(x, y, iter | (iter << 8));
whatever iter is is plugged into the lower bits and also shifted by 8 bits which corersponds to the Green value in the middle.
So I guess you could try
I.setRGB(x, y, iter << 12);
This will plug the iter value in the upper bits (Red Green).
Upvotes: 1