CODEWITHSUNDEEP
c#genericsactionfunctorfunc
Constructor
Constructor

Reputation: 7473

How to simplify the code with two overloads of the function that get Func and Action as a parameter?

  1. Is it a way to make such code simpler? Yes, I know that the code in the comment can be extracted as a method, but it is a bit confusing to write such two overloads every time. Note that there can be other parameters than functor in a function like DoSomething.

    Result DoSomething<Result>(Func<Parameter, Result> functor)
{
    // do something to construct argument
    return functor(argument);
}

void DoSomething(Action<Parameter> functor)
{
    // do something to construct argument
    functor(argument);
}

  2. More complex variant. How to achieve the same result without code duplication if a functor call is inside a using block?

In fact I want to find a C# alternative to the C++14 code like

template <class Functor>
auto DoSomething(Functor functor)
{
    // do something...
    return functor(argument);
}

Upvotes: 2

Views: 109

Answers (1)

zmbq
zmbq

Reputation: 39013

Well, you could create a FuncWrapper<Parameter, Result> generic class with implicit conversions from Func<Parameter, Result> and Action<Parameter> and a Call(Parameter) function that performs the actual call.

The FuncWrapper can have two members (a Func<...> and Action<...>) and call through the one that isn't null, or you can wrap the Action<...> with a lambda expression that essentially turns it into a Func<...> (call the action, return default(Result))

Then you define just one function in your class:

Result DoSomething(FuncWrapper<Parameter, Result> wrapper)
{
    // Find argument
    return wrapper.Call(argument);
}

Your FuncWrapper class should return default(Result) value in case the Action<Parameter>.

Upvotes: 1

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