CODEWITHSUNDEEP
bashshellsh
Andrei Cristian Popescu
Andrei Cristian Popescu

Reputation: 25

Using find grep together

I am trying to make a command to get all the files from the current folder and it's subtree that ends with a suffix then them need to contain lines which start's with a capital letter and and with !. I spent some to find a solution. I only found how to print the lines which starts with capital character but i don't know how to put in the command that '!'.

This is to find all the files which contains a line starting with a capital letter. How do i add to look for lines which ends with !.

find . -type f -exec grep -l "^[A-Z]+*" {} +

Upvotes: 0

Views: 197

Answers (3)

mrjink
mrjink

Reputation: 1129

find . -type f -name '*suffix' -print0 | xargs -r0 grep -le '^[A-Z].*!$' should do what you want.

It finds all files (-type f) with a suffixed name (-name '*suffix') and feeds those files to grep using xargs. The regular expression then finds lines that begin with a capital and end with an exclamation mark.

The problem here is mostly quoting. The ! is special in bash (and other shells) and refers to the history. You need to escape it, either by using single quotes or escaping it, by prepending a backslash.

Upvotes: 0

anubhava
anubhava

Reputation: 785038

You can use this regex in grep:

find . -type f -exec grep -El '^[[:blank:]]*[A-Z].*![[:blank:]]*$' {} +

Upvotes: 1

usamazf
usamazf

Reputation: 3215

Following syntax will be useful. If am getting the question right this is the solution for you:

find . -type f -name '*!.*' -exec grep -l "^[A-Z]+*" {} +

Upvotes: 0

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