Reputation: 1468
I am new to code-igniter. In my View I added this code to enable google login in my website.
<html lang="en">
<head>
<meta name="google-signin-scope" content="profile email">
<meta name="google-signin-client_id" content="720765566138-5c6jreo4r7ma6cm0hdblj5cmjtdiruk4.apps.googleusercontent.com">
<script src="https://apis.google.com/js/platform.js" async defer> </script>
</head>
<body>
<div class="g-signin2" data-onsuccess="onSignIn" data-onfailure="onFailure" data-theme="dark"></div>
<script>
function onFailure(msg){ console.log(msg); }
function onSignIn(googleUser) {
console.log("onSignIn");
var profile = googleUser.getBasicProfile();
var user_name = profile.getName();
var id = googleUser.getAuthResponse().id;
};
</script>
</body>
</html>
How can I send the variable user_name and id to the Controller so that I can call the Model to insert the value to the database.
Upvotes: 2
Views: 3493
Reputation: 2218
You can simply use ajax to post the information once you've gotten it (using jquery below):
<script>
function onSignIn(googleUser)
{
var profile = googleUser.getBasicProfile();
var user_name = profile.getName();
var id = googleUser.getAuthResponse().id;
$.ajax({
'url': 'the/path/to/controller',
'type': 'POST',
'data':{'user_name': user_name, 'id':id},
'success': function(){}, //up to you
'error': function() // up to you
})
};
</script>
Upvotes: 2
Reputation: 2587
With normal Subbmission of your Form
or using Ajax
if your method is post
$this->input->post();
this method contain all data else by default get method
$this->input->get();
Make your form
Like below
<form action="baseurl/controller_name/method">
add hidden field of user_id then sumbmit
</form>
In Your Controller
function YOUR_METHOD()
{
print_r($this->input->get())//By default get method
}
Upvotes: 2
Reputation: 472
You have to make controller's action and in this you have to pass variable like this :
function test{
$user_name = "XYZ";
$this->load->view('view_name', $user_name);
}
If you want to pass more than one variable then use below :
function test{
$user_name = "XYZ";
$data = 123;
$this->load->view('view_name', array("user_name"=>$user_name,"data"=>$data));
}
May this will help you :)
Upvotes: 2