CODEWITHSUNDEEP
javastring
Paul Erdem Bursh
Paul Erdem Bursh

Reputation: 77

How to get a string from a line in Java?

I have this line of strings: 

String line = "GET /MyFile.extension  HTTP/1.1\n\n"

I want to get only the the file name MyFile.extension string, I tried this but the problem the HTTP version could change.

String fileName = line.replace("GET /", "");
fileName = fileName.replace(" HTTP/1.1", "");

This doesn't work too:

string fileName = line.indexOf("MyFile.extension");

I don't know the file Name too, it could be any file, It there a way to get that file between the strings "GET/" and "HTTP/"?

Upvotes: 1

Views: 514

Answers (3)

Aniruddha Shevle
Aniruddha Shevle

Reputation: 4909

    public static void main(String []args)
    {
       String line = "GET /MyFile.extension  HTTP/1.1\n\n";

       // To find the index of "/"
       int start = line.indexOf("/");

       // To find the index of space from int start which I got from the line above
       int end = line.indexOf(" ", start);

       // To extract the given string from the start+1 index to the end index 
       String s = line.substring(start+1, end);

       System.out.println(s);       
    }

Output :

MyFile.extension

Upvotes: 1

Oliver Hemsted
Oliver Hemsted

Reputation: 563

You could use regular expression to get you in the inner value

Pattern p = Pattern.compile("GET (.*?) HTTP/1.1")
Matcher m = p.matcher(s);
if (m.find()) {
  System.out.println(m.group(1)); // MyFile.extension
}

Upvotes: 0

ninja.coder
ninja.coder

Reputation: 9648

You can simple do this: line.split(" ")[1].substring(1)

Here is the code snippet:

public static void main (String[] args)
{
    String line = "GET /MyFile.extension  HTTP/1.1\n\n";
    System.out.println(line.split(" ")[1].substring(1));
}

Output:

MyFile.extension

Upvotes: 1

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