CODEWITHSUNDEEP
neo4jcypher
ChrisE
ChrisE

Reputation: 576

Multiple neo4j node join: "This query builds a cartesian product between disconnected patterns"

I'm running this query:

MATCH (a:TEST:LOC1),(b:TEST_JOIN:LOC1),(c:TEST:LOC1)
WHERE a._out = b._in and b._out = c._in and c._text = 'P'
CREATE (a)-[r:TEST_JOIN]->(c)

It runs very slowly, and the execution plan says: "This query builds a cartesian product between disconnected patterns"

All the properties are indexed and I have tried:

MATCH (c:TEST:LOC1) where c._text='P' with c
MATCH (a:TEST:LOC1),(b:TEST_JOIN:LOC1)
WHERE a._out = b._in and b._out = c._in
CREATE (a)-[r:TEST_JOIN]->(c)

Sorry if this is basic. Does anyone know how to optimise this? Many thanks in advance.

Upvotes: 3

Views: 1177

Answers (2)

Evgen
Evgen

Reputation: 1338

I would try this

MATCH (c:TEST:LOC1) where c._text='P' with c
MATCH (b:TEST_JOIN:LOC1) where b._out = c._in with b, c
Match (a:Test:LOC1) WHERE a._out = b._in with a, c
CREATE (a)-[r:TEST_JOIN]->(c)

Upvotes: 8

Clark Richey
Clark Richey

Reputation: 392

The problem is that amongst your 3 nodes (a, b and c) there are no relationships. You are asking the database to grab all a nodes ,all b nodes and all c nodes and then filter the down by your where clause. That's a cartesian product (https://en.wikipedia.org/wiki/Cartesian_product) and its an indication that your model is incorrect.

Based on your comments it sounds like you want relationships like

 (a)-[something]->(b)-[somethingElse]->(c)

That is something you need to setup before you do your query so that you can use cypher to match based on a graph pattern.

Upvotes: 0

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