Reputation: 8025
I am trying to write my own train test split function using numpy instead of using sklearn's train_test_split function. I am splitting the data into 70% training and 30% test. I am using the boston housing data set from sklearn.
This is the shape of the data:
housing_features.shape #(506,13) where 506 is sample size and it has 13 features.
This is my code:
city_data = datasets.load_boston()
housing_prices = city_data.target
housing_features = city_data.data
def shuffle_split_data(X, y):
split = np.random.rand(X.shape[0]) < 0.7
X_Train = X[split]
y_Train = y[split]
X_Test = X[~split]
y_Test = y[~split]
print len(X_Train), len(y_Train), len(X_Test), len(y_Test)
return X_Train, y_Train, X_Test, y_Test
try:
X_train, y_train, X_test, y_test = shuffle_split_data(housing_features, housing_prices)
print "Successful"
except:
print "Fail"
The print output i got is:
362 362 144 144
"Successful"
But i know it was not successful because i get a different numbers for the length when i run it again Versus just using SKlearn's train test function and always get 354 for the length of X_train.
#correct output
from sklearn.cross_validation import train_test_split
X_train, X_test, y_train, y_test = train_test_split(housing_features, housing_prices, test_size=0.3, random_state=42)
print len(X_train)
#354
What am i missing my my function?
Upvotes: 2
Views: 12391
Reputation: 31662
Because you're using np.random.rand
which gives you random numbers and it'll be close to 70% for 0.7 limit for very big numbers. You could use np.percentile
for that to get value for 70% and then compare with that value as you did:
def shuffle_split_data(X, y):
arr_rand = np.random.rand(X.shape[0])
split = arr_rand < np.percentile(arr_rand, 70)
X_train = X[split]
y_train = y[split]
X_test = X[~split]
y_test = y[~split]
print len(X_Train), len(y_Train), len(X_Test), len(y_Test)
return X_train, y_train, X_test, y_test
EDIT
Alternatively you could use np.random.choice
to select indices with your desired amount. For your case:
np.random.choice(range(X.shape[0]), int(0.7*X.shape[0]))
Upvotes: 4