Reputation:
Write an algorithm that takes an array and moves all of the zeros to the end, preserving the order of the other elements.
For example:
moveZeros([false,1,0,1,2,0,1,3,"a"]) // returns[false,1,1,2,1,3,"a",0,0]
My code:
var moveZeros = function (arr) {
var zeros = [];
var others = [];
var res;
var arrayLength = arr.length;
for (var i = 0; i < arrayLength; i++) {
if (arr[i] == 0) {
zeros.push(arr[i]);
} else {
others.push(arr[i]);
}
}
var res = others.concat( zeros );
return res;
}
I get the following result:
Expected: ["a","b",null,"c","d",1,false,1,3,[],1,9,{},9,0,0,0,0,0,0,0,0,0,0],
Instead got: ["a","b",null,"c","d",1,1,3,1,9,{},9,0,0,0,false,0,0,[],0,0,0,0,0]
The expected result is quite close to what I achieved (see above) . I don't understand why I have false
in a different place?
Upvotes: 1
Views: 6005
Reputation: 1
var arr = [false,1,0,1,2,0,1,3,"a"]
function moveZeros(arr){
var zeros = [];
var others = [];
var output;
for (var i=0; i< arr.length; i++){
if (arr[i]===0){
zeros.push(arr[i]);
}else{
others.push(arr[i])
}
}
output = others.concat(zeros);
console.log(output);
}
moveZeros([false,1,0,1,2,0,1,3,"a"]);
Upvotes: 0
Reputation: 1
You could use the filter()
method to achieve your goal. With the arrow notation you can shorten the code. For example: arr => arr === 0
is the shorthand for the anonymous filter function function(arr) { return arr === 0; }
var moveZeros = function (arr) {
const zeros = arr.filter (arr => arr === 0);
const others = arr.filter (arr => arr !== 0);
return others.concat(zeros);
}
Upvotes: 0
Reputation: 1
var titleCase = function(title) {
var arr = [];
for (i = 0; i < title.length ; i++) {
if (title[i] !== 0 ) {
arr.push(title[i]);
}
}
for (i = 0 ; i < title.length ; i++) {
if (title[i] == 0 ) {
arr.push(title[i]);
}
}
return arr;
}
Upvotes: 0
Reputation: 386560
Use Array#splice()
and Array#push()
.
function moveZeros(a) {
var i = a.length - 1;
while (i--) {
if (a[i] === 0) {
a.push(a.splice(i, 1)[0]);
}
}
return a;
};
var array = [false, 1, 0, 1, 2, 0, 1, 3, "a"];
document.write('<pre>' + JSON.stringify(moveZeros(array), 0, 4) + '</pre>');
Another approach with swapping items.
function moveZeros(array) {
var length = array.length,
i = length;
while (--i) {
if (array[i] !== 0) continue;
length--;
while (i < length) {
[array[i + 1], array[i]] = [array[i], array[i + 1]];
i++;
}
}
return array;
}
var array = [false, 1, 0, 1, 2, 0, 1, 3, "a"];
console.log(...moveZeros(array));
Upvotes: 2
Reputation: 89
The code snippet below should work , please try , reason for null is that the length of the arr starts count from zero so when using <=
you should subtract 1 from the total length.
var moveZeros = function (arr) {
// TODO: Program me
let zero = []
let others = []
let together = []
for (let i =0; i <= arr.length-1; i++){
if (arr[i] === 0){
zero.push(arr[i])
}
else{
others.push(arr[i])
}
}
together = others.concat(zero)
return together
}
Upvotes: 0
Reputation: 67207
Try to use a normal for loop
and splice
at this context to make your job done,
var arr = [false,1,0,1,2,0,1,3,"a"];
for(var i=arr.length;i>0;i--){
if(arr[i] === 0){ arr.push(arr.splice(i,1).pop()); }
}
console.log(arr); //[false, 1, 1, 2, 1, 3, "a", 0, 0]
document.body.innerHTML += JSON.stringify(arr);
Upvotes: 2
Reputation: 68393
try this simply
var arr = [false,1,0,1,2,0,1,3,"a"];
arr.sort(function(a,b){if (a===0){return 1}});
document.body.innerHTML += JSON.stringify(arr);
Upvotes: 2
Reputation: 424
Please use === operator to compare if value is 0:
if (arr[i] === 0) {
zeros.push(arr[i]);
} else {
others.push(arr[i]);
}
Upvotes: 0