CODEWITHSUNDEEP
c++infinite-loop
katang
katang

Reputation: 2774

Breaking out from generating windows in infinite loop

In my program I made an obvious typo

for(int i = 0; i<mNoOfCores; i+3)

instead of

for(int i = 0; i<mNoOfCores; i++)

Unfortunately, in the loop I was generating QT5 windows. So my Ubuntu system was absolutely denied, I could only restart after power-on reset. (the mouse was responsive, and probably so was the keyboard, too.) Is there a better method? Or, in this way I can deny my OS from an application?

Upvotes: 0

Views: 77

Answers (1)

vcp
vcp

Reputation: 962

There is no way for compiler to inform you in advance about infinite loops. This is discussed at many places, here, here, here.

What you can do is use simple "double checks" to prevent yourself from hanging the OS. Example:

int totalNoWindowsCreated = 0; // keep track of windows created OK
for(int i = 0; i<mNoOfCores; i+3)
{
  // Create window  
  totalNoWindowsCreated++; // If created OK
  assert(("Bug !", totalNoWindowsCreated <= mNoOfCores)); // Check
}

UPDATE: Of course, you can make mistake in assert condition, in that case, just take a break and drink coffee :).

Upvotes: 1

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