CODEWITHSUNDEEP
phpformatting
Haim Evgi
Haim Evgi

Reputation: 125456

Percentage display issue

i have a value that i calculate between 0 -100 , its usually a float number like 5.87876 , so i use number_format like :

$format_number = number_format($number, 2, '.', '');

the problem is , even the calculate number is integer like : 100

its show 100.00

but i want to display it like : 100

what is the elegant way to achive this ?

(i mean without else if ..)

Upvotes: 2

Views: 653

Answers (2)

bjelli
bjelli

Reputation: 10070

so you are trying to have an accuracy of two decimal places after the dot, but suppress the .00 on integers? I'd use sprintf:

$numbers = Array(3.141, 5.87876, 10.9999, 100);


foreach( $numbers as $n ) {
    $string = sprintf("%6.2f\n", $n);
    $string = str_replace(".00", "   ", $string);
    echo $string;
}

The output is

  3.14
  5.88
 11   
100

Upvotes: 2

Pekka
Pekka

Reputation: 449385

This is the shortest way I know. 

$digits =        (is_numeric($number) && intval($number) == $number ? 0 : 2);
$format_number = number_format($number, $digits, '.', '');

The is_numeric and intval trick is taken from this SO question

Upvotes: 4

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